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Brrunno [24]
2 years ago
14

Sam decides to build a square garden. If the area of the garden is 4x2 + 28x + 49 square feet, what is the length of one side of

the garden?
A. (2x + 7) feet
B. (7x + 2) feet
C . (2x − 7) feet
D. (7x − 2) feet
Mathematics
2 answers:
xenn [34]2 years ago
8 0

Answer:

A. (2x+7)

Step-by-step explanation:

Zinaida [17]2 years ago
7 0
The formula of a square area is A = L²
so if A = 4x2 + 28x + 49, so the other length is <span>A. (2x + 7) feet
proof 

L=</span>(2x + 7), L²= (2x + 7)² =4x2 + 28x + 49,
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Answer:

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Step-by-step explanation:

Given,

Consider a rectangle ABCD.

Let AC be a diagonal of rectangle of length   = 15

In triangle  ABC.

Sin 45° =height/hypotenuse   {SinФ = height / hypotenuse}

Here, hypotenuse = diagonal of rectangle ( i.e AC = 15)

And height is AB

Therefore, sin 45° = AB/AC

or sin 45° = AB / 15

or 1/√2 = AB /15

AB = 15/√2

Similarly we can find Base (i.e BC) using cosine.

Cos 45° = Base/Hypotenuse

Cos 45° = BC / AC

or  1/√2 = BC/15

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And width of rectangle , BC = 15/√2

Therefore, area of rectangle = Length × Width

Area of rectangle = 15/√2  ×   15/√2  = 225/2

Hence, area of rectangle = 225/2 = 112.5

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