We have to simplify
sec(θ) sin(θ) cot(θ)
Now first of all let's simplify these separately , using reciprocal identities.
Sec(θ) = 1/cos(θ)
Sin(θ) is already simplified
Cot(θ)= cos(θ) / sin(θ) ,
Let's plug these values in the expression
sec(θ) sin(θ) cot(θ)
= ( 1/cos(θ) ) * ( sin(θ) ) * ( cos(θ) / sin(θ) )
= ( sin(θ) /cos(θ) ) * ( cos(θ) /sin(θ) )
sin cancels out with sin and cos cancels out with cos
So , answer comes out to be
=( sin(θ) /cos(θ) ) * ( cos(θ) /sin(θ) )
= 1
If you cut that in half you would get 8. 64 is a square root.
Answer:60?
Step-by-step explanation:
260%=2.6
156/2.6
Answer:
try the second one because it is the smallest and close togehet so maybe that means that the mean is closer to the number and it nots some outlier.
Step-by-step explanation:
Answer:
1194 students last year
Step-by-step explanation:
The problem statement tells us ...
98% × (students last year) = 1170
Dividing by 98%, we get ...
1170/0.98 = (students last year) = 1193.88 ≈ 1194
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<em>Check</em>
1170/1194 = 0.979899... ≈ 0.98 = 98%