Answer:
The answer is 0.2. It is an irrational number with a repeating 2. It should have a line over the two to represent it repeating.
Step-by-step explanation:
First divide 2 by 9.
Use a calculator or do it by hand.
You get your answer.
Answer:
Not factorable.
Step-by-step explanation:
We have a trinomial (3 terms). We factor by splitting the middle term 4t into factors of -7 (the last term) which add to 4.
-7 = 1 * -7
4t= 1t+-7t doesn't work
4t=-1t+7t doesn't work
This is not factorable.
(8x 2 −15x)−(x 2 −27x)=ax 2 +bxleft parenthesis, 8, x, squared, minus, 15, x, right parenthesis, minus, left parenthesis, x, squ
quester [9]
Answer:
<h2>5</h2>
Step-by-step explanation:
Given the expression (8x² −15x)−(x² −27x) = ax² +bx, we are to determine the value of b-a. Before we determine the vwlue of b-a, we need to first calculate for the value of a and b from the given expression.
On expanding the left hand side of the expression we have;
= (8x² −15x)−(x² −27x)
Open the paranthesis
= 8x² −15x−x²+27x
collect the like terms
= 8x²−x²+27x −15x
= 7x²+12x
Comparing the resulting expression with ax²+bx
7x²+12x = ax²+bx
7x² = ax²
a = 7
Also;
12x = bx
b =12
The value of b - a = 12 - 7
b -a = 5
Hence the value of b-a is equivalent to 5
Let us first define Hypotenuse Leg (HL) congruence theorem:
<em>If the hypotenuse and one leg of a right angle are congruent to the hypotenuse and one leg of the another triangle, then the triangles are congruent.</em>
Given ACB and DFE are right triangles.
To prove ΔACB ≅ ΔDFE:
In ΔACB and ΔDFE,
AC ≅ DF (one side)
∠ACB ≅ ∠DFE (right angles)
AB ≅ DE (hypotenuse)
∴ ΔACB ≅ ΔDFE by HL theorem.
Answer:16.05 $
Step-by-step explanation: Put all the numbers in a vertical format and add them all up
9.95
+1.15
+4.95
--------
16.05
