Ask question

Ask question

All categories

3 years ago

13

Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26

1 answer:

arsen [322]3 years ago

7 0

So, let's say the number is x.

5(x + 27) ≥ 6( x + 26)

You might be interested in

HELLPPPP LIKE ASAP PLEASE!! Each of these numbers represents the score that a student got on a set of math tests. What is the me

sleet_krkn [62]

Answer:

81.66 repeating

Step-by-step explanation:

86+72+65+82+91+94=490

490÷6=81.66 repeating

EDIT: this answer is false

6 0

3 years ago

Read 2 more answers

Please hurry I will mark you brainliest.

ivann1987 [24]

Answer:

12862.83cm³

Step-by-step explanation:

Volume of the Box: [L×W×H] or [30x30x30] or [27000cm³]

Volume of the Sphere: [ $\frac{4}{3}\pi r^{3}$ ] ( $\pi$ =pi=3.14) (r=radius=15) or [ $\frac{4}{3}$ ×3.14×3375] or [14137.17cm³]

Volume of the empty space: 27000cm³-14137.17cm³=12862.83cm³

Btw there are online tools to help you find the volume of a sphere (just use it after you understand the equation)

Hope I helped!

4 0

2 years ago

How many feet of fencing would a farmer need if she wanted

Sauron [17]

Answer:

Well, it's the perimeter, so...40.

You just calculate the perimeter of a rectangle with the lenght of 12 and width of 8, by the formula

$P = 2L+2W$

or you can factor it out.

7 0

3 years ago

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

2 years ago

The soccer team collected $800 at a car wash fundraiser. They charged $5.00 for small vehicles and $10.00 for larger vehicles. T

Amiraneli [1.4K]

Answer:

60

Step-by-step explanation:

Substitute 50 for y in the formula

5x+10y=800

5x+10*50=800

5x+500=800

5x=800-500

5x=300

x=300/5

x=60

3 0

2 years ago

Read 2 more answers