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3 years ago

9

A bag contains 5 red marbles, 3 blue marbles, 7 yellow marbles, and 2 green marbles. Which ratio can be used to compare the yell

ow marbles to the blue marbles?

2 answers:

Licemer1 [7]3 years ago

6 0

Answer:

7:3

Step-by-step explanation:

The number of yellow marbles: the number of blue marbles

PilotLPTM [1.2K]3 years ago

3 0

Answer:

7:3

Step-by-step explanation:

there are 7 yellow marbles and 3 blue marbles

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3/5 TIMES 1/2 WHOEVER ANSWERES IN UNDER 2 MINUTS I WILL MARK BRAINLIEST AND ILL GIVE YOU EXTRA POINTS

Ostrovityanka [42]

Step-by-step explanation:

3/10 or 0.3

hope it helps:))!

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2 years ago

Read 2 more answers

The SAT mathematics scores in the state of Florida for this year are approximately normally distributed with a mean of 500 and a

creativ13 [48]

99.7%

This is because the likelihood of a point being within 2 SDs of the mean is 99.7%.

7 0

3 years ago

3 questions in 1

MrRissso [65]

Answer:

1. D. 20, 30, and 50

2. A. 86

3. B. 94

Step-by-step explanation:

1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.

The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.

Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.

Thus:

Q1 = (85 + 87)/2 = 86

Q3 = (93 + 95)/2 = 94

IQR = Q3 - Q1 = 94 - 86

IQR = 8

Outliers in the data set are data values below the lower limit or above the upper limit.

Let's find the lower and upper limit.

Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74

The data values below the lower limit (74) are 20, 30, and 50

Let's see if we have any data value above the upper limit.

Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106

No data value is above 106.

Therefore, the only outliers of the data set are:

D. 20, 30, and 50

2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.

Thus:

Q1 = (85 + 87)/2 = 86

3. Q3 = (93 + 95)/2 = 94

3 0

2 years ago

Sixty-eight percent of adults in a certain country believe that life on other planets is plausible. You randomly select five adu

Pavlova-9 [17]

Answer:

Mean = 3.4

Variance = 1.088

Standard deviation = 1.0431

Step-by-step explanation:

$P=0.68\\ \\N=5$

The mean of a binomial distribution with parameters N (the number of trials) and p (the probability of success for each trial) is $m=N\cdot p$

Thus,

$m=5\cdot 0.68=3.4$

The variance of the binomial distribution is $s^2=Np(1-p)$ , where $s^2$ is the variance of the binomial distribution, so

$s^2=5\cdot 0.68\cdot (1-0.68)=3.4\cdot 0.32=1.088$

The standard deviation $s$ is the square root of the variance $s^2,$ so

$s=\sqrt{1.088}\approx 1.0431$

3 0

2 years ago

The total sales of a company (in millions of dollars) t months from now are given by S(t) = 0.03t3 + 0.5t2 + 9t + 4. Find S'(t).

o-na [289]

Answer:

S'(t) = 0.09t^2 + t + 9

S(2) = 24.24

S'(2) = 11.36

S(11) = 203.43 means that the sales of the company 11 months from now is $203,430,000.

S'(11) = 30.89 means that, 11 months from now, the rate at which sales change is $30,890,000 per month

Step-by-step explanation:

The derivate of the sales function S'(t) , which is the rate at which sales vary with time in months, is:

$\frac{dS(t)}{dt} =S'(t) = 0.09t^2 + t + 9$

S(2) is found by applying t=2 to S(t):

$S(2) = 0.03*(2^3) + 0.5*(2^2) + 9*2 + 4\\S(2)= 24.24$

S'(2) is found by applying t=2 to S'(t):

$S'(2) = 0.09*(2^2) + 2 + 9\\S'(2) = 11.36$

Since the sales function gives the amount of sales in millions of dollars,

S(11) = 203.43 means that the sales of the company 11 months from now is $203,430,000.

S'(t) represents the rate of change in sales in millions of dollars per month.

S'(11) = 30.89 means that, 11 months from now, the rate at which sales change is $30,890,000 per month

8 0

2 years ago