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Firlakuza [10]
3 years ago
5

Helpppppppp plz I'm not rlly good at area

Mathematics
1 answer:
Nitella [24]3 years ago
6 0
For number 8, the area will be 350 square yard because the total area of the rectangle is 20 times 18 will equal 360 square yards, and I know that the area of the cutting rectangle is 5 times 2 equals 10 square yard, so the rest of the rectangle will be 360-10 or 350 square yards. For number 9, the area will be 28 square meters because the area of the whole rectangle is 40 square meters, and I found the area of the rectangle that already cut which equal 4 times 3 equal 12 square meters, so the area of the rectangle that does not cut will be 40-12 or 28 square meters. For number 10, the answer will be 92 square feet because the area of the complete rectangle wipp be 14 times 10 equal 140 square feet, and the area of the rectangle that already cut is 8 timed 6 equal 48 square feet, so the area that had left will equal 140-48 or 92 square feet. Hope it help!
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If there is an increase in the money supply that causes prices to rise and
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Answer:

The answer is B.

Step-by-step explanation:

5 0
4 years ago
A vector with magnitude 9 points in a direction 190 degrees counterclockwise from the positive x axis. Write in component form
Over [174]

Answer:

\vec{v}= \text{ or } \approx

Step-by-step explanation:

Component form of a vector is given by \vec{v}=, where i represents change in x-value and j represents change in y-value. The magnitude of a vector is correlated the Pythagorean Theorem. For vector \vec{v}=, the magnitude is ||v||=\sqrt{i^2+j^2.

190 degrees counterclockwise from the positive x-axis is 10 degrees below the negative x-axis. We can then draw a right triangle 10 degrees below the horizontal with one leg being i, one leg being j, and the hypotenuse of the triangle being the magnitude of the vector, which is given as 9.

In any right triangle, the sine/sin of an angle is equal to its opposite side divided by the hypotenuse, or longest side, of the triangle.

Therefore, we have:

\sin 10^{\circ}=\frac{j}{9},\\j=9\sin 10^{\circ}

To find the other leg, i, we can also use basic trigonometry for a right triangle. In right triangles only, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse of the triangle. We get:

\cos 10^{\circ}=\frac{i}{9},\\i=9\cos 10^{\circ}

Verify that (9\sin 10^{\circ})^2+(9\cos 10^{\circ})^2=9^2\:\checkmark

Therefore, the component form of this vector is \vec{v}=\boxed{}\approx \boxed{}

6 0
3 years ago
PLEASE HELP!!! ASAP!!!!!!!!!!!!!!! 10 POINTS
I am Lyosha [343]
1800|2\\.\ 900|2\\.\ 450|2\\.\ 225|5\\.\ \ 45|5\\.\ \ \ 9|3\\.\ \ \ 3|3\\.\ \ \ 1|\\\\1880=2\cdot2\cdot2\cdot5\cdot5\cdot3\cdot3=2^3\cdot5^2\cdot3^2\\\\Answer:\ \boxed{2^3\cdot3^2\cdot5^2}

\sqrt[3]{320}\\\\320|2\\160|2\\.\ 80|2\\.\ 40|2\\.\ 20|2\\.\ 10|2\\.\ \ 5|5\\.\ \ 1|\\\\320=2\cdot2\cdot2\cdot2\cdot2\cdo2\cdot5=2^3\cdot2^3\cdot5=2^3\cdot2^3\cdot\\\\\sqrt[3]{320}=\sqrt[3]{2^3\cdot2^3\cdot5}=\sqrt[3]{2^3}\cdot\sqrt[3]{2^3}\cdot\sqrt[3]{5}=2\cdot2\sqrt[3]{5}=4\sqrt[3]5\\\\Answer:\ \boxed{\sqrt[3]{320}=4\sqrt[3]{5}}
4 0
3 years ago
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Simplify the following expression
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3 years ago
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Another 3rd grade question:
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To find the perimeter you would need to add 35+35+65+65=200. If the perimeter is 200, and he circles around it 4 times, 200*4=800, which is the answer. 
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