Basically, r=2t
A(r)=pir^2
sub 2t for r
A(2t)=pi(2t)^2
A(2t)=4pit²
A. A=4pit²
B. t=5
A=4pi5²
A=4pi25
A=100pi
A=314 square units
Answer:
9 fits perfectly...not sure why there's a range....
Answer:
-4
Step-by-step explanation:
Solve this like a normal equation. Pretend the ≤ is an equal sign. Then isolate the variable. Subtract 7 from both sides, and that will give you -4
Seventy five dollars hope this could help[
17.50 - 4.50 = $13 she really can make a business off of this
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