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olchik [2.2K]
3 years ago
15

The Family Fine Arts Center charges $21 per adult and $13 per senior citizen for its performances. On a recent weekend evening w

hen 535 people paid admission, the total receipts were $8355. How many who paid were senior citizens?
I am struggling with the right formula to use.
Do I use an arthimetic or geometric sequence?
Mathematics
1 answer:
uysha [10]3 years ago
3 0

Answer:

175 adults

360 senior citizens

Step-by-step explanation:

Let x be the number of senior citizens

There were a total of 535 people, so

(535-x)=total number of adults

Total receipts=$8,355

Adult payments+Senior payments=$8,355

21(535-x)+13x=$8,355

$11,235-21x+13x=$8,355

$11,235-8x=$8,355

-8x=$-2,880

x=360 senior citizens

Number of adults=535-360=175 adults

To check, just substitute...

21(175)+13(360)

3,675+4,680

Which equals.....

$8,355

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z=\frac{4.6-4.8}{\frac{0.9}{\sqrt{180}}}=-2.98    

p_v =P(Z  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis,and we have enough evidence to conclude that the true mean is significantly lower thn 4.8 at 10% of signficance.  

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Data given and notation  

\bar X=4.6 represent the sample mean

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n=180 sample size  

\mu_o =4.8 represent the value that we want to test

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We need to conduct a hypothesis in order to check if thetrue mean is below the specifications, the system of hypothesis would be:  

Null hypothesis:\mu \geq 4.8  

Alternative hypothesis:\mu < 4.8  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

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We can replace in formula (1) the info given like this:  

z=\frac{4.6-4.8}{\frac{0.9}{\sqrt{180}}}=-2.98    

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Since is a one sided test the p value would be:  

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