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taurus [48]
3 years ago
9

The nearest star to the Earth is the red dwarf star Proxima Centauri, at a distance of 4.218 light-years. Convert this distance

to barleycorns. (1barleycorn=1/3 inch.)
Physics
1 answer:
alukav5142 [94]3 years ago
3 0

Explanation:

The nearest star to the Earth is the red dwarf star Proxima Centauri, at a distance of 4.218 light-years.  

Light year is the unit of distance covered by the heavenly bodies. 1 light year is equal to :

1\ light\ year=3.72\times 10^{17}\ inches

So, 4.218\ light\ year=4.218\times 3.72\times 10^{17}\ inches

4.218\ light\ year=1.56\times 10^{18}\ inches

We need to convert 4.218 light-years barley corns.  

Since, 1 barleycorn = 1/3 inch  

1\ inch=3\ barleycorn

1.56\times 10^{18}\ inches=3\times 1.56\times 10^{18}=4.68\times 10^{18}\ barleycorn

So, the nearest star to the Earth is at a distance of 4.68\times 10^{18}\ barleycorn. Hence, this is the required solution.

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Determine the launch speed of a horizontally launched projectile that lands 26.3m from the base of a 19.3m high cliff.
atroni [7]

The launch velocity of the projectile is 13.28 m/s.

What is projectile motion?

The motion of an object thrown in the air under the force of gravity is known as projectile motion.

Since the object is launched horizontally, its initial velocity along the vertical direction is zero. From the second kinematic equation,

s=u*t+(1/2)at^2.

where s is the displacement, t is the time, u is the initial velocity and a is the acceleration. Since the height is decreasing, so it will be taken negative.

For the vertical motion, s=-19.3 m, a=-9.8 m/s^2 and u=0. Put the values in the above equation and solve it.

-19.3 = (0)*t+(1/2)*(-9.8)*t^2

19.3 = (1/2)*(9.8)*t^2

t=1.98 s

Since the velocity along the horizontal direction is constant, the displacement along the horizontal direction is given by the formula,

X=vt

where X is the horizontal displacement, v is the initial horizontal velocity and t is the time.

For the horizontal motion, X=26.3 m and t=1.98 s. Put the values in this equation and solve it.

26.3=v*(1.98)

v=13.28 m/s

The launch velocity is equal to the initial horizontal velocity, so it is equal to 13.28 m/s.

Learn more about projectile motion.

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4 0
2 years ago
A hockey puck is struck so that it slides at a constant speed and strikes the far side of the rink, 58.2 m away. The shooter hea
DENIUS [597]

Answer:

v = 33.66 m/s

Explanation:

Let hockey puck is moving at constant speed v

so here we have

d = vt

so time taken by the puck to strike the wall is given as

t = \frac{58.2}{v}

now time taken by sound to come back at the position of shooter is given as

t_2 = \frac{58.2}{340}

t_2 = 0.17s

so we know that total time is 1.9 s

1.9 = t + t_2

1.9 = t + 0.17

1.9 - 0.17 = t

t = 1.73 s

now we have

1.73 = \frac{58.2}{v}

v = 33.66 m/s

7 0
3 years ago
The same ball is shot straight up a second time from the same gun, but this time the spring is compressed only half as far befor
Mekhanik [1.2K]

Answer:

The new height the ball will reach = (1/4) of the initial height it reached.

Explanation:

The energy stored in any spring material is given as (1/2)kx²

This energy is converted to potential energy, mgH, of the ball at its maximum height.

If the initial height reached is H

And the initial compression of the spring = x

So, mgH = (1/2)kx²

H = kx²/2mg

The new compression, x₁ = x/2

New energy of loaded spring = (1/2)kx₁²

And the new potential energy = mgH₁

mgH₁ = (1/2)kx₁²

But x₁ = x/2

mgH₁ = (1/2)k(x/2)² = kx²/8

H₁ = kx²/8mg = H/4 (provided all the other parameters stay constant)

6 0
3 years ago
Filtration is used to separate mixtures based on _____.
sergejj [24]
Based on particle size.
its where a solid is separated from a liquid. filter paper has tiny holes only allowing small molecules to pass
8 0
3 years ago
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Is an object speeding up or slowing down of the V final is greater than the V initial?
sertanlavr [38]

Answer:

V is greater

Explanation:

because v intial at that time V final is the that speed which it is going at that time

7 0
3 years ago
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