1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mars2501 [29]
3 years ago
5

An atom of element X has one more shell of electrons than an atom of beryllium, but it has one less valence electron than beryll

ium. Which element is element X?
sodium (Na)

boron (B)

magnesium (Mg)

lithium (Li)
Physics
2 answers:
3241004551 [841]3 years ago
8 0
The correct answer is Sodium
KengaRu [80]3 years ago
7 0

Answer:

sodium (Na)

Explanation:

The valence electron configuration of the given elements are as follows:

Sodium (Na) = 3s¹

Boron (B) = 2s²2p¹

Magnesium (Mg) = 3s²

Lithium (Li) = 2s¹

The valence electron configuration of beryllium (Be) = 2s²

The outer shell in Na is 3s i.e. n = 3 relative to that of Be where n = 2

Also the valence shell in Na has 1 s electron i.e. one electron lower than Be.

You might be interested in
What is the electric current measured in
cluponka [151]

An ampere (AM-pir), or amp

6 0
2 years ago
What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3 = 55.0 nC placed between q1
notka56 [123]

Complete Question

Part of the question is shown on the first uploaded image

The rest of the question

What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3 = 55.0 nC placed between q1 and q2 at x3 = -1.220 m ? Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures.

Answer:

The net force exerted on the third charge is  F_{net}=  3.22*10^{-5} \ J

Explanation:

From the question we are told that

    The third charge is  q_3 =  55 nC =  55 *10^{-9} C

    The position of the third charge is  x = -1.220 \ m

     The first charge is q_1 =  -16 nC  =  -16 *10^{-9} \ C

     The position of the first charge is x_1 =  -1.650m

      The second charge is  q_2 =  32 nC  =  32 *10^{-9} C

      The position of the second charge is  x_2 =   0  \ m  

The distance between the first and the third charge is

      d_{1-3} =  -1.650 -(-1.220)

     d_{1-3} = -0.43 \ m

The force exerted on the third charge by the first is  

     F_{1-3} =  \frac{k  q_1 q_3}{d_{1-3}^2}

Where k is the coulomb's constant with a value  9*10^{9} \ kg\cdot m^3\cdot s^{-4}\cdot A^2.

substituting values

      F_{1-3} =  \frac{9*10^{9}* 16 *10^{-9} * (55*10^{-9})}{(-0.43)^2}

       F_{1-3} = 4.28 *10^{-5} \ N

 The distance between the second and the third charge is      

  d_{2-3} =  0- (-1.22)

   d_{2-3} =1.220 \ m

The force exerted on the third charge by the first is mathematically evaluated as

       F_{2-3} =  \frac{k  q_2 q_3}{d_{2-3}^2}

substituting values

       F_{2-3} =  \frac{9*10^{9} * (32*10^{-9}) *(55*10^{-9})}{(1.220)^2}

       F_{2-3} =  1.06*10^{-5} N

The net force is

      F_{net} =  F_{1-3} -F_{2-3}

substituting values

    F_{net} = 4.28 *10^{-5} - 1.06*10^{-5}

    F_{net}=  3.22*10^{-5} \ J

6 0
3 years ago
A dolphin can swim at a constant speed of 12.5 m/s. How
myrzilka [38]

Answer:

\boxed {\tt 3.6 \ seconds}

Explanation:

Time can be found by dividing the distance by the speed.

t=\frac{d}{s}

The distance is 45 meters and the speed is 12.5 meters per second.

d= 45 \ m \\s= 12.5 \ m/s

t=\frac{45 \ m}{12.5 \ m/s}

Divide. Note that the meters, or "m" will cancel each other out.

t=\frac{45 }{12.5 \ s}

t=3.6 \ s

It will take the dolphin 3.6 seconds to swim a distance of 45 meters are 12.5 meters per second.

6 0
3 years ago
Read 2 more answers
When the spacecraft is at the halfway point, how does the strength of the gravitional force on the spaceprobe by Earth compre wi
mixer [17]

Solution :

When the spacecraft is at halfway point, the distance from the Earth as well as Mars are same. We have to account the masses of the planets. The gravitational force that is exerted by the Earth is greater because of its combined mass with the space probe.

The mass of Earth is greater than the mass of Mars. Therefore, the force of Earth is more than Mars.

5 0
3 years ago
1. explain why mid-sized cars and SUVs have different rollover fatality rates.
iris [78.8K]

Answer:

1.  They generally have poorer fuel efficiency and require more resources to manufacture than smaller vehicles, thus contributing more to climate change and environmental degradation. Their higher center of gravity increases their risk of rollovers.

2. Mid-sized cars and SUVs both have a fixed object fatality rate of 2.6/BVM. This is most likely because they have a similar mass and inertia. The force of the crash is likely to have about the same deceleration in both vehicles.

Explanation:

brainliest please

8 0
3 years ago
Other questions:
  • While running these tests, crall notices a similarity in the velocity measured at the ground independent of whether the tennis b
    8·2 answers
  • which of following categories of small bodies in the solar system does ceres belong to?. . . A.Dwarf Planets. B.Comets. C.Astero
    6·2 answers
  • which of the following can best help you in a risky situation? stay close to the quieter kids have an excuse ready so you can le
    14·2 answers
  • 12. One object has half the mass of another object. The first object also has half the ---.
    7·1 answer
  • What is the magnitude of the velocity after it hits the ground?
    10·1 answer
  • Please answer will mark brainleist
    11·2 answers
  • Question 1
    14·1 answer
  • A parachute on a racing dragster opens and changes the speed of the car from 93 m/s to 45 m/s in a period of 5.3 seconds. What i
    6·1 answer
  • PLEASE HELP ASAP<br>Explain how can a ripple tank be used to view wave pattern.
    10·1 answer
  • compare and contrast the excited state and the ground state of electrons. please use proper grammar and mechanics.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!