Answer:
I have answer with explanations in each of the six (6) special cases.
Explanation:
Please find attached the detailed solution to all your questions.
Hey I hope you have a great rest of your day god bless
Answer:
1.11×10¹⁹ electrons
Explanation:
The formula for electric energy is given as,
E = QV ................. Equation 1
Where E = Electric Energy, Q = charge, V = Voltage.
Make Q the subject of the equation
Q = E/V............... Equation 2
Given: E = 8 W, V = 4.5 V.
Substitute into equation 2
Q = 8/4.5
Q = 1.778 C
using,
n = Q/e............ Equation 3
Where n = number of electron, e = Charge of one electron.
Given: e = 1.6×10⁻¹⁹ C
Substitute into equation 3
n = 1.778/1.6×10⁻¹⁹
n = 1.11×10¹⁹ electrons
Answer:
t = (ti)ln(Ai/At)/ln(2)
t = 14ln(16)/ln(2)
Solving for t
t = 14×4 = 56 seconds
Explanation:
Let Ai represent the initial amount and At represent the final amount of beryllium-11 remaining after time t
At = Ai/2^n ..... 1
Where n is the number of half-life that have passed.
n = t/half-life
Half life = 14
n = t/14
At = Ai/2^(t/14)
From equation 1.
2^n = Ai/At
Taking the natural logarithm of both sides;
nln(2) = ln(Ai/At)
n = ln(Ai/At)/ln(2)
Since n = t/14
t/14 = ln(Ai/At)/ln(2)
t = 14ln(Ai/At)/ln(2)
Ai = 800
At = 50
t = 14ln(800/50)/ln(2)
t = 14ln(16)/ln(2)
Solving for t
t = 14×4 = 56 seconds
Let half life = ti
t = (ti)ln(Ai/At)/ln(2)
