(a) what are the x and y components of each vector?
For vector v1:
v1 = 6.6 (cos (180) i + sine (180) j)
v1 = 6.6 (-1i + 0j)
v1 = -6.6i
For vector v2:
v2 = 8.5 (cos (55) i + sine (55) j)
v2 = 8.5 ((0.573576436) i + (0.819152044) j)
v2 = 4.88 i + 6.96 j
(b) determine the sum v v 1 2
The sum of both vectors is given by:
v1 + v2 = (-6.6i) + (4.88 i + 6.96 j)
Adding component to component:
v1 + v2 = (-6.6 + 4.88) i + (6.96) j
v1 + v2 = (-1.72) i + (6.96) j
You need to write it out such as number 8 would be 10x10x10x10 so for every number on top you multiply the number by itself
Answer:
x>1
Step-by-step explanation:
move the constant to the right side and change its sign 7x>10-3
Then subtract the numbers 7x>7
Then divide the inequality by 7 from for both sides.
x>1
Powers of 4 are like 4^1, 4^2, 4^3 and so on
remember that 4^x means 4 times itself x times for example
4^3=4 times iteslef 3 times=4 times 4 times 4
so the multipules of the powers of 4 are just 4 times of the previous
so we will list
4^1=4
4^2=16
4^3=64
4^4=256
4^5=1024
1024 is already more than 1000 so the list stops and is
1,16,64,256
820 divided by 42 is 19.52 times
