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4 years ago

8

Please do this problem, and if you are able to, please tell me how you did it! ;-D

2 answers:

11111nata11111 [884]4 years ago

8 0

Bottom chunk is 4 by 4, so that part has 16 blocks. The next one up is 4 by 3 so that one is 12 blocks. Second from the top is 4 by 2, this chunk has 8 blocks. The very top chunk is 2 by 1, this one has only 2 blocks.

1. Altogether there are 38 blocks. I added all the chunks together.

Does this give you a starting point? I don't want to give you the answer strait up. Think about it. I believe in you. Let me know if you need more help.

geniusboy [140]4 years ago

6 0

I think 6-8 cubes have 0 sides showing
Not sure;)

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Please help me out and show work

lina2011 [118]

Answer:

$s(x)=\frac{0.2}{x+5}$

Step-by-step explanation:

In 5 liters, there is 4% salt.

Lets find liters of salt.

First, converting 4% to decimal (dividing by 100):

4% = 4/100 = 0.04

0.04 * 5 = 0.2

So, there is 0.2 liters of salt.

Now, x liters of water is added to total, so total is now:

5 + x

The concentration of salt will be amount of salt divided by amount of salt water solution.

Amount of salt = 0.2 (as seen above)

Amount of new salt water solution = x + 5

So,

Concentration of salt in new solution is $\frac{0.2}{x+5}$

2nd choice is right.

4 0

3 years ago

Translate from words into math notation:<br><br> The sum of 2 and 4 gives 6

shepuryov [24]

Answer:

X+2+4=6

Step-by-step explanation:

I HOPE IT HELP.......

6 0

3 years ago

Find the value of f(1) and f(0)

sergeinik [125]

Answer:

Step-by-step explanation:suppose

Our equation be x^2+2x +1

When f(x)= 1

Substitute 1 in our equation. 1+2+1 /( we get like this)

=4

When f(0)= 0+0+1. =1

Thank you

5 0

3 years ago

Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt

Paladinen [302]

Answer:

$y(x)=4a\sqrt{3}* sin(x)-3a$

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

$\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}$

But:

$\frac{1}{tan(x)} =cot(x)$

So:

$\frac{dy(x)}{dx} =cot(x)*(3a+y)$

Multiplying both sides by dx and dividing both sides by 3a+y:

$\frac{dy}{3a+y} =cot(x)dx$

Integrating both sides:

$\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx$

Evaluating the integrals:

$log(3a+y)=log(sin(x))+C_1$

Where C1 is an arbitrary constant.

Solving for y:

$y(x)=-3a+e^{C_1} sin(x)$

$e^{C_1} =constant$

So:

$y(x)=C_1*sin(x)-3a$

Finally, let's evaluate the initial condition in order to find C1:

$y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a$

Solving for C1:

$C_1=4a\sqrt{3}$

Therefore:

$y(x)=4a\sqrt{3}* sin(x)-3a$

3 0

4 years ago

What is 50.8 divided by 2.54

Veseljchak [2.6K]

It's 20.

Hope this helps <3

5 0

3 years ago

Read 2 more answers