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Setler [38]
4 years ago
9

Where is lithium used in the body?

Chemistry
2 answers:
Ilya [14]4 years ago
7 0

Answer:

Lithium is a naturally occurring alkali metal, which living organisms ingest from dietary sources and which is also present in trace amounts in the human body. In much higher concentrations, lithium is effective as a medication for mania and mood swings including manic depressive disorders

kolezko [41]4 years ago
3 0

Answer:

Hiya there ^w^

Explanation:

Lithium is a naturally occurring alkali metal, which living organisms ingest from dietary sources and which is also present in trace amounts in the human body. In much higher concentrations, lithium is effective as a medication for mania and mood swings including manic depressive disorders.

<em><u>Hope this helped!</u></em> :D

Credit sourced from "pubmed.ncbi.nlm.nih.gov"

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lana [24]

Answer:

Option D. Saturated alkane

Explanation:

To know which option is correct, it is important that we know what saturated and unsaturated compounds are in this context.

Saturated hydrocarbons are compounds which has only carbon to carbon single bonds (C–C) in its chain. A very good example of such compound is the Alkanes.

Unsaturated hydrocarbons are compounds which has either a carbon to carbon double bond (C=C) or a carbon to carbon triple bond (C≡C) in its chain. Examples of such compounds include alkenes and alkynes.

Now, let us answer the question given above bearing the meaning of saturated and unsaturated compounds in mind.

The compound given above contains only carbon to carbon (C–C) single bond.

Therefore, the compound is a saturated alkane.

5 0
3 years ago
The atomic symbol mc025-1.jpg represents potassium-40 (K-40), a radioactive isotope that has 19 protons and 21 neutrons. Which a
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The answer is a 40/18Ar
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A 34.57 mL sample of an unknown phosphoric acid solution is titrated with a 0.127 M sodium hydroxide solution. The equivalence p
Bas_tet [7]

<u>Answer:</u> The concentration of unknown phosphoric acid solution is 0.034 M

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_3PO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=3\\M_1=?M\\V_1=34.57mL\\n_2=1\\M_2=0.127M\\V_2=28.2mL

Putting values in above equation, we get:

3\times M_1\times 34.57=1\times 0.127\times 28.2\\\\M_1=\frac{1\times 0.127\times 28.2}{3\times 34.57}=0.034M

Hence, the concentration of unknown phosphoric acid solution is 0.034 M

7 0
3 years ago
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Answer: Ok

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2 years ago
In comparing a 0.25 molality aqueous NaCl solution to a 0.25 molality aqueous CaCl 2 solution:
4vir4ik [10]

Answer:

d

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higher no of particles are in CaCl2 solution

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3 years ago
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