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4 years ago

Where is lithium used in the body?

Chemistry

2 answers:

Ilya [14]4 years ago

7 0

Answer:

Lithium is a naturally occurring alkali metal, which living organisms ingest from dietary sources and which is also present in trace amounts in the human body. In much higher concentrations, lithium is effective as a medication for mania and mood swings including manic depressive disorders

kolezko [41]4 years ago

3 0

Answer:

Hiya there ^w^

Explanation:

Hope this helped! :D

Credit sourced from "pubmed.ncbi.nlm.nih.gov"

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Which describes the molecule shown below?

lana [24]

Answer:

Option D. Saturated alkane

Explanation:

To know which option is correct, it is important that we know what saturated and unsaturated compounds are in this context.

Saturated hydrocarbons are compounds which has only carbon to carbon single bonds (C–C) in its chain. A very good example of such compound is the Alkanes.

Unsaturated hydrocarbons are compounds which has either a carbon to carbon double bond (C=C) or a carbon to carbon triple bond (C≡C) in its chain. Examples of such compounds include alkenes and alkynes.

Now, let us answer the question given above bearing the meaning of saturated and unsaturated compounds in mind.

The compound given above contains only carbon to carbon (C–C) single bond.

Therefore, the compound is a saturated alkane.

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3 years ago

The atomic symbol mc025-1.jpg represents potassium-40 (K-40), a radioactive isotope that has 19 protons and 21 neutrons. Which a

otez555 [7]

The answer is a 40/18Ar

6 0

3 years ago

Read 2 more answers

A 34.57 mL sample of an unknown phosphoric acid solution is titrated with a 0.127 M sodium hydroxide solution. The equivalence p

Bas_tet [7]

Answer: The concentration of unknown phosphoric acid solution is 0.034 M

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_3PO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=3\\M_1=?M\\V_1=34.57mL\\n_2=1\\M_2=0.127M\\V_2=28.2mL$

Putting values in above equation, we get:

$3\times M_1\times 34.57=1\times 0.127\times 28.2\\\\M_1=\frac{1\times 0.127\times 28.2}{3\times 34.57}=0.034M$

Hence, the concentration of unknown phosphoric acid solution is 0.034 M

7 0

3 years ago

HELP PLS DUE TODAY

Rina8888 [55]

Answer: Ok

Explanation: Explanation:Using recombinant DNA technology to modify an organism's DNA to achieve desirable traits is called genetic engineering. Addition of foreign DNA in the form of recombinant DNA vectors that are generated by molecular cloning is the most common method of genetic engineering.

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2 years ago

In comparing a 0.25 molality aqueous NaCl solution to a 0.25 molality aqueous CaCl 2 solution:

4vir4ik [10]

Answer:

Explanation:

higher no of particles are in CaCl2 solution

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3 years ago