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Serga [27]
3 years ago
15

How many formulas units are in 3.11 mole of Ca(NO3)2 can you show your work by step by step correct answer

Chemistry
2 answers:
Lyrx [107]3 years ago
4 0

Answer:

18.73× 10²³ formula units

Explanation:

Given data:

Number of moles of Ca(NO₃)₂ = 3.11 mol

Number of formula units = ?

Solution:

Avogadro number:  

"It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance"  

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

Number of formula units of Ca(NO₃)₂:

1 mole contain 6.022 × 10²³ formula units

3.11 mol ×  6.022 × 10²³ formula units / 1 mol

18.73× 10²³ formula units

Fittoniya [83]3 years ago
4 0

Thank you lord lord please thank you lord lord for that you lor

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How many oxygen atoms are in 4.00g of quartz?
Rufina [12.5K]

Answer:

Rounding for significant figures gives us a final answer of 3.41×1022 atoms 3.41 × 10 22 a t o m s atoms of oxygen.

4 0
2 years ago
If you know the poh of a solution how can you determine its ph
Sati [7]
POH+pH=14,
so
pH=14-pOH
7 0
3 years ago
national defense, currency, post office, foreign affairs, & interstate commerce. b. charter local governments, education, pu
katen-ka-za [31]

Answer And Explanation:

Option C is correct.

Lend and borrow money, taxation, law enforcement, charter banks and transportation.

Some of the powers that were mentioned in the other options that weren't concurrent powers (that is, they belong to either the state government alone or the federal government alone) & disqualified them from being the answer include:

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3 0
3 years ago
Assume the weight of an average adult is 70. kg, and that 420. kJ of heat are evolved per mole of oxygen consumed as a result of
seraphim [82]

Answer:

The temperature difference of the body after 3 hours = 5.16 K

Explanation:

we know that the number of moles of O₂ inhaled are 0.02 mole/min⁻¹

                                   or, 1.2 mole.h⁻¹

The average heat evolved by the oxidation of foodstuffs is then:

⇒          Q avg =\frac{1.2 X 420 X 10^{3} }{70} = 7.2 kj.h⁻¹.Kg⁻¹

the heat produced after 3 h would be:

                 =    7.2 kj. h⁻¹.Kg⁻¹ x 3 h

                 = 21.6 kj. kg⁻¹

                 = 21.6 x 10³ j kg⁻¹

We know Qp = Cp x ΔT

Assume the heat capacity of the body is 4.18 J g⁻¹K⁻¹

⇒ ΔT = \frac{Qp}{Cp}

⇒ ΔT = \frac{(21.6 X 10^{3} j.kg^{-1} ) }{(4.18 j k^{-1}g^{-1})   X (1000g.kg^{-1} )}

⇒ ΔT = 5.16 K

6 0
3 years ago
A certain ore is 37.3% nickel by mass how many kilograms of this ore would you need to dig up to have 10.0g of nickel
jeka57 [31]
If the grade of the ore is 37.3% nickel, then the unknown quantity to get 10 grams of nickel is 0.373 x = 10 grams or x = 10/0.373=26.8 grams or 0.0268 kg needed to dig up to recover the 10 grams of nickel. At this grade of ore, 1 kilogram would yield 373 grams of nickel. 
7 0
3 years ago
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