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3 years ago

14

Each tree in the orchard had exactly 118 apples on it. The number of apples in the whole orchard was 2,242. How many apple trees

were in the orchard?

2 answers:

sergejj [24]3 years ago

7 0

118×2242
= 264,556
this is the answer

Lapatulllka [165]3 years ago

5 0

Answer:

the actual answer is 19 because you have to divide 2242 by 118 to get the answer

Step-by-step explanation:

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Which angle is congruent to BGC?

lawyer [7]

Answer:

BFC makes this angle add up to 90 degree at BFD

Therefore it becomes complementary to angle CFD

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There are 448 reams of paper in thw supply room. Fourteen reams are used each day. At that rate, how many days will the supply o

Mnenie [13.5K]

X = number of days that have passed

448 = 14x

divide both sides by 14

32 = x

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Which dimensions can create more than one triangle?

garri49 [273]

Answer:

three sides measuring 4 ft, 8 ft, and 10 ft

Step-by-step explanation:

To choose which dimensions that can create more than one triangle, we consider the given values carefully and how possible it will be to construct.

The only dimensions given in the option that will be possible to create more than one triangle from it, is three sides measuring 4 ft, 8 ft, and 10 ft.

4 ft, 8 ft, and 10 ft are in simple multiple of 2

4 ft, 8 ft, and 10 ft = 2 (2 ft, 4 ft, and 5 ft ), with this we can construct two triangles with three sides measuring 2 ft, 4 ft, and 5 ft.

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3 years ago

Two ships leave a harbor together, traveling on courses that have an angle of 135°40' between them. If they each travel 402 mile

mario62 [17]

Answer:

Therefore they are 734.106 miles apart.

Step-by-step explanation:

Given that ,

Two ships have a harbor together. The angle between two ships is 135°40'. Each of two ships travel 402 miles.

It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.

Let ∠B= 135°40', and AB = 402 miles , BC = 402 miles

Then the distance between the ships = AC

We know

The sum of all angles = 180°

⇒∠A+∠B+∠C=180°

⇒∠A+135°40'+∠C=180°

⇒2∠A= 180°- 135°40' [ since ∠A=∠C]

⇒2∠A=44°60'

⇒∠A= 22°30'

Again we know that,

$\frac{AB}{sin\angle C}=\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}$

Taking last two ratio,

$\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}$

Putting the value of BC , AC ,∠A,∠B

$\frac{402}{sin 22^\circ30'}=\frac{AC}{sin 135^\circ40'}$

$\Rightarrow AC=\frac{402 \times sin135^\circ40'}{sin 22^\circ30'}$

≈734.106 miles

Therefore they are 734.106 miles apart.

3 0

3 years ago

Determine the lengths of the sides of the rectangle using the given area. Give answers both exactly and

Degger [83]

Answer:

Part a) Exactly values

The width of the rectangle is $\frac{\sqrt{70}}{2}\ cm$

The length of the rectangle is $2\sqrt{70}\ cm$

Part b) Approximately values

The width of the rectangle is $4.2\ cm$

The length of the rectangle is $16.7\ cm$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The area of rectangle is equal to

$A=LW$

we have

$L=4x\ cm\\W=x\ cm$

substitute the values in the formula

$A=4x(x)$

$A=4x^2$

$A=70\ cm^2$

so

$70=4x^2$

Solve for x

Divide by 4 both sides

$\frac{70}{4}=x^2$

square root both sides

$x=(+/-)\frac{\sqrt{70}}{2}$

The solution is the positive value

$x=\frac{\sqrt{70}}{2}$

therefore

<em>Exactly values</em>

$L=4\sqrt{70}}{2}=2\sqrt{70}\ cm\\\\W=\frac{\sqrt{70}}{2}\ cm$

<em>Approximately values</em>

$L=4\sqrt{70}}{2}=16.7\ cm\\\\W=\frac{\sqrt{70}}{2}=4.2\ cm$

6 0

3 years ago