Answer:
BFC makes this angle add up to 90 degree at BFD
Therefore it becomes complementary to angle CFD
X = number of days that have passed
448 = 14x
divide both sides by 14
32 = x
Answer:
three sides measuring 4 ft, 8 ft, and 10 ft
Step-by-step explanation:
To choose which dimensions that can create more than one triangle, we consider the given values carefully and how possible it will be to construct.
The only dimensions given in the option that will be possible to create more than one triangle from it, is three sides measuring 4 ft, 8 ft, and 10 ft.
4 ft, 8 ft, and 10 ft are in simple multiple of 2
4 ft, 8 ft, and 10 ft = 2 (2 ft, 4 ft, and 5 ft ), with this we can construct two triangles with three sides measuring 2 ft, 4 ft, and 5 ft.
Answer:
Therefore they are 734.106 miles apart.
Step-by-step explanation:
Given that ,
Two ships have a harbor together. The angle between two ships is 135°40'. Each of two ships travel 402 miles.
It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.
Let ∠B= 135°40', and AB = 402 miles , BC = 402 miles
Then the distance between the ships = AC
We know
The sum of all angles = 180°
⇒∠A+∠B+∠C=180°
⇒∠A+135°40'+∠C=180°
⇒2∠A= 180°- 135°40' [ since ∠A=∠C]
⇒2∠A=44°60'
⇒∠A= 22°30'
Again we know that,

Taking last two ratio,

Putting the value of BC , AC ,∠A,∠B


≈734.106 miles
Therefore they are 734.106 miles apart.
Answer:
Part a) Exactly values
The width of the rectangle is 
The length of the rectangle is 
Part b) Approximately values
The width of the rectangle is 
The length of the rectangle is 
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The area of rectangle is equal to

we have

substitute the values in the formula



so

Solve for x
Divide by 4 both sides

square root both sides

The solution is the positive value

therefore
<em>Exactly values</em>

<em>Approximately values</em>
