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puteri [66]
2 years ago
8

Question is in the image

Mathematics
1 answer:
Rudik [331]2 years ago
4 0
The unit rate that the turtle is crawling is: (1/23)/(5/6) = (1/23)*(6/5) = 6/115 miles/hour.
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Part A
labwork [276]

An <em>algebraic expression</em> is one that consists of both <u>number(s)</u> and an <u>alphabet(s)</u>. The <em>required</em> answers are:

i. Distance from Chenoa's <u>house</u> to the <em>coffee shop</em> = 6.0 miles

ii. D<u>istance</u> from <em>coffee shop</em> to Chenoa's <u>school</u> = 1.5 miles

iii. <em>Distance</em> from Chenoa's <u>house</u> to her <u>school</u> = 7.5 miles

An <em>algebraic expression</em> is one that consists of both <u>number(s)</u> and an <u>alphabet(s)</u>. The <em>alphabet</em> is referred to as the <u>unknown</u> whose <u>value</u> has to be <em>determined</em>.

In the given question, let the <u>distance</u> from the <em>coffee shop</em> to Chenoa's <u>school</u> be represented by y.

So that;

The <u>distance</u> from Chenoa's house to the <em>coffee shop</em> = (2y + 3) miles.

The <em>total distance</em> from Chenoa's <u>house</u> to her <u>school </u>= 5y.

This implies that:

(2y + 3) + y = 5y

3y + 3 = 5y

3 = 5y - 3y

2y = 3

y = \frac{3}{2}

  = 1.5

The <em>distance</em> from the <em>coffee shop</em> to Chenoa's <u>school</u> is 1.5 miles.

Thus;

(2y + 3) = ( 2(1.5) + 3)

            = 6

The <u>distance</u> from Chenoa's <u>house</u> to the <em>coffee shop</em> is 6 miles.

And,

5y = 5(1.5)

    = 7.5

The <em>total distance</em> from Chenoa's <u>house</u> to her <u>school</u> is 7.5 miles.

For more clarifications on algebraic expressions, visit: brainly.com/question/12792264

#SPJ1

5 0
2 years ago
Wayne drove 2 miles west and then 6 miles south, how far is he from his starting point?
suter [353]

Answer:

8 miles away

Step-by-step explanation:

Add the 6 miles and the 2 miles together.

6 0
3 years ago
A semicircle is cut out of a rectangular paperboard 24in long and 18n wide, as shown below. What is the perimeter of the paperbo
svet-max [94.6K]

Answer:

Perimeter of the paperboard that remains after the semicircle is removed = 94.26 in

Step-by-step explanation:

Watch the attached figure of how the semi circle is cut out of the rectangular paperboard.

Length = 24 in

Width = 18 in

Radius of the semi circle = Half of the width of the paperboard = \frac{18}{2} = 9 in

1) Circumference of the semi circle = π*radius

= 3.14*9

= 28.26 in

2) Perimeter of the paperboard that remains after the semicircle is removed

= Top + Left + Bottom + Right Circumference of the semi circle

= 24 + 18 + 24 + 28.26

= 94.26 in


5 0
3 years ago
Solve for y. 3y – 12 = –6                                           A. –54          B. 2          C. 18          D. –6
erastova [34]
3y - 12 = -6
3y = 6                 | Add 12 to both sides
 y = 2                  | Divide by 3 on both sides


Answer: y = 2 (Answer B)
8 0
3 years ago
Read 2 more answers
Help me please. Plzzzz.
Deffense [45]
16 is going to be right
8 0
3 years ago
Read 2 more answers
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