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AURORKA [14]
3 years ago
8

All BUT ONE could be a reason for the color variation in the mice. That is

Biology
2 answers:
sammy [17]3 years ago
7 0
D) asexual reproduction
Kazeer [188]3 years ago
7 0

Asexual reproduction results in genetic sameness, not genetic variation.

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natita [175]
Question:why were maggots there only after the flies left
Hypotheses:the maggots are fly larva
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3 years ago
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You are doing an experiment and plated E. coliin different medias. Media A has onlyglucose, B has only lactose, and media C has
krek1111 [17]

Answer:

A. Glucose:

As lactose is absent will follow the glucose metabolism, so the lac repressor will hold tightly with the operator which leads to the prevention of transcription as RNA polymerase can not bind to promoter so no lactose metabolism.

B. lactose:

In the case or wild mutant lactose metabolism will occur as lactose is present, allolactose binds to the lac repressor thus the operator and promoter are free so transcription starts.  The same result will be in all test except in the case of a mutant repressor.

C. glucose and lactose:

In this case, diauxic growth will occur. This growth takes place when two sugars are present in the media. The preferred sugar will be consumed first That is glucose. Then a lag phase will come which will be followed by the second sugar metabolism that is lactose.  the given two cases :

Lactose will be metabolized first, as operator site mutation prevents repressor protein binding and thus will lead to the constitutive synthesis of lac operon in test B.   The same thing will happen, as in this case also, constitutive synthesis of lac operon will happen in test C.

Cultures grown in the presence of both glucose and lactose are metabolizing lactose. In the test (b) and (c) will be responsible due to constitutive synthesis of lac operon will happen.

6 0
3 years ago
Animals will lick up ethylene glycol (antifreeze) due to its sweet taste. the antidote for ethylene glycol poisioning is the adm
maw [93]

Answer:

Fomepizole with ethanol

Explanation:

The antidote for ethylene glycol poisioning is the administration of fomepizole with ethanol.

Ethylene glycol (antifreeze) is a poisonous, colorless and sweet tasting liquid which is usually used for antifreeze formulations. Drinking or liking of ethylene glycol deliberately or unintentionally can result in ethylene glycol poisoning. The poisoning can be treated by stabilizing the affected animal, followed by the administration of the antidote; fomepizole with ethanol. This is the most preferred antidote. Hemodialysis, sodium bicarbonate and magnesium may also be used to treat the affected animal.

5 0
3 years ago
Cho đoạn mạch ADN có trình tự sắp xếp như sau
allochka39001 [22]

Answer:

C, T, A, C

Explanation:

I think it will be like this. I can't understand your language but I think my answer will help you Insha'Allah.

7 0
3 years ago
Anaerobic glucose breakdown produces a compound called _____ that accumulates in the tissues and blood.
umka2103 [35]
Anaerobic breakdown of glucose produces lactic acid, which accumulates in the tissues and blood.
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3 years ago
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