Help please asap!!!!
2 answers:
You might be interested in
Hey there :)
- tan²x + sec²x = 1 or 1 + tan²x = sec²x
sin²x + cos²x = 1
Divide the whole by cos²x
so 
and
so 
Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}
1 = - tan²x = sec²x or sec²x - tanx = 1
- tan²x + sec²x = 1 or 1 + tan²x = sec²x
sin²x + cos²x = 1
Divide the whole by cos²x
and
Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}
1 = - tan²x = sec²x or sec²x - tanx = 1
Answer:
The sum of the two vectors is the vector <-0.5 , 4+3.5 >
Step-by-step explanation:
The horizontal component (x) of a vector whose magnitude is b units and its direction is Ф° is b cos Ф
The vertical component (y) of a vector whose magnitude is b and its direction is Ф is b sin Ф
The vector is <b cos Ф , b sin Ф>
∵ The vector goes 7 units at an angle
- That means its magnitude is 7 and its direction is
∴ x = 7 cos( )
∴ y = 7 sin( )
∵ cos( ) =
∵ sin( ) =
- Substitute them in x and y
∴ x = (7)( )
∴ x = -3.5
∴ y = (7)( )
∴ y = 3.5
∴ The vector is <-3.5 , 3.5>
Now lets add the vectors by adding xs and ys components
∵ <3 , 4> + <-3.5 , 3.5 > = <3 + -3.5 , 4 + 3.5
>
∴ <3 , 4> + <-3.5 , 3.5> = <-0.5 , 4+3.5
>
∴ The sum of the two vectors is the vector <-0.5 , 4+3.5 >