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3 years ago

Is this right I just need a yes or no answer (working on slope)

Mathematics

1 answer:

sveticcg [70]3 years ago

4 0

Neither is correct. please try again and re-ask for answers or hint.

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4-(2x-3)=3 whats the answer

Oxana [17]

Hello there.

Explanation:

↓↓↓↓↓↓↓↓↓↓

$4-(2x-3)=3$

First, subtract by 4 from both sides.

$4-(2x-3)-4=3-4$

Second, simplify.

$-(2x-3)=-1$

Third, divide by -1 from both sides.

$\frac{-(2x-3)}{-1}=\frac{-1}{-1}$

Fourth, simplify.

$2x-3=1$

Next, add by 3 from both sides.

$2x-3+3=1+3$

Then simplify.

$2x=4$

Therefore, divide by 2 from both sides.

$\frac{2x}{2}=\frac{4}{2}$

Finally, simplify.

$x=2$

<u><em>Answer⇒⇒⇒⇒x=2</em></u>

Hope this helps!

Thank you for posting your question at here on Brainly.

-Charlie

8 0

3 years ago

In RSM camp, there are four counselors for every fifty seven students and three teachers for every five counselors.

Ray Of Light [21]

Answer:

Students : Counselors : Teachers = 285: 20 : 12

Step-by-step explanation:

In the camp, the ratio of:

( C: S ) Counselors : Students is 4 : 57

( T: C ) Teachers : Counselors is 3 : 5

To determine the ratio of - Students : Counselors : Teachers

Here given - C : S = 4 : 57

Multiplying both sides by 5, we get

C: S = 4 x 5 : 57 x 5 = 20 : 285

So, for every 20 counselors, there are 285 students ...... (1)

Similarly, given Teachers : Counselors is 3 : 5

Multiplying both sides by 4, we get

T : C = 3 x 4 : 5 x 4 = 12 : 20

So, for every 12 teachers, there are 20 Counselors ...... (2)

Hence, in both equation 1 and 2 the number of counselors is same = 20 .

Hence, both the ratios acne be combined.

So we get C : S = 20 : 285 and T : C = 12: 20

Inverting the values

⇒ S : C = 285 : 20 and C : T = 20 : 12

or, S : C : T = 285: 20 : 12

or, Students : Counselors : Teachers = 285: 20 : 12

Hence, for every 285 students there are 20 counselors and 12 teachers.

4 0

3 years ago

What is the result when 6x^3+25x^2+20x+46x

goldenfox [79]

Answer:

The answer to your question is 2x² - 29x + 26

Step-by-step explanation:

dividend = 6x³ - 25x² + 20x + 4

divisor = 3x + 2

2x² - 29x + 26

3x + 2 6x³ - 25x² + 20x + 4

-6x³ - 4x²

0 - 29x² + 20x

+ 29x² + 58x

0 78x + 4

-78x - 52

0 - 48

quotient = 2x² - 29x + 26

remainder = -48

Result = 2x² - 29x + 26 - 48/6x³ - 25x² + 20x + 4

6 0

3 years ago

Multiply and reduce 4x^2/3*(9/x)3

Lilit [14]

So you follow the steps and i hope this will be easy for you .

4 0

3 years ago

Segment PE has endpoints P(-4,4) and E(0,-4). Find the coordinates of point Q such that PQ:QE is 1:3. Enter the coordinates belo

Natalka [10]

Answer:

(-3, 2)

Step-by-step explanation:

Given that point Q, partitions segment PE, such that PQ:QE is 1:3, coordinates of point Q is found using the formula below:

$x = \frac{mx_2 + nx_1}{m + n}$

$y = \frac{my_2 + ny_1}{m + n}$

Where,

$P(-4, 4) = (x_1, y_1)$

$E(0, -4) = (x_2, y_2)$

$m = 1, n = 3$

Plug in the necessary values to find x and y coordinates for point Q as follows:

$x = \frac{mx_2 + nx_1}{m + n}$

$x = \frac{1(0) + 3(-4)}{1 + 3}$

$x = \frac{0 - 12}{4}$

$x = \frac{-12}{4}$

$x = -3$

$y = \frac{my_2 + ny_1}{m + n}$

$y = \frac{1(-4) + 3(4)}{1 + 3}$

$y = \frac{-4 + 12}{4}$

$y = \frac{8}{4}$

$y = 2$

The coordinates of the point Q are (-3, 2))

8 0

3 years ago