All categories

3 years ago

What happens when polar molecules are between oppositely charged metal plates

Physics

1 answer:

KatRina [158]3 years ago

7 0

Answer:

They will become aligned according to the charges on the metal plate.

Explanation:

When Polar molecules are placed between oppositely charged metal plates the molecules will tend to be attracted by their corresponding oppositely charged plates that is the positive and negative plates,

A polar molecule is one which has opposite charges on its ends. Non-polar molecules however do not have charges on their end

You might be interested in

A monarchy is the type of government that the colonist do not want true or false

Hoochie [10]

Answer:

Monarchy is rule from kings and queens

Explanation:

4 0

4 years ago

A 0.144kg baseball is pitched horizontally at 38.0 m/s. After the baseball is hit by the bat, it moves at the same speed, but in

Hoochie [10]

Answer:

Given:

mass of the ball m = 0.144 kg

velocity v = 38 m/s

now, change in momentum

P = m v- ( - mv)

= 2 mv

=2 x (0.144) x (38)

= 10.944 kg-m/s

Impulse J= F. Δt

change in momentum is equal to impulse

J = 10.944 kg-m/s

we know force is equal to change in momentum per unit time

$F = \dfrac{P}{t}$

$F = \dfrac{10.944}{0.8\times 10^{-3}}$

F = 13.68 x 10³ N

F = 13.68 kN

3 0

4 years ago

An SUV has a mass of 6000 kg and a compact car has a mass of 2000 kg. They both go around the same unbanked circular curve on th

Evgen [1.6K]

Answer:

Therefore, the centripetal acceleration of the SUV is <u>3 times</u> ao of the compact car.

Explanation:

FOR SUV:

$ac_{suv} = \frac{mv^2}{r}\\$

where,

ac_suv = centripetal acceleration of the SUV = ?

m = mass of SUV = 6000 kg

v = speed of SUV = vo

r = radius of path

Therefore,

$ac_{suv} = \frac{6000\ vo^2}{r}\\$ ---------------- equation (1)

FOR CAR:

$ao = \frac{mv^2}{r}\\$

where,

ao = centripetal acceleration of the car = ?

m = mass of car = 2000 kg

v = speed of car = vo

r = radius of path

Therefore,

$ao = \frac{2000\ vo^2}{r}\\$ --------------------- equation (2)

Dividing equation (1) by eq(2):

$\frac{ac_{suv}}{ao} = \frac{6000}{2000}\\\\ac_{surv} = 3ao$

Therefore, the centripetal acceleration of the SUV is <u>3 times</u> ao of the compact car.

8 0

3 years ago

Some radar systems detect the size and shape of objects such as aircraft and geological terrain. What is the frequency of such a

vova2212 [387]

Answer:

$f=1.57\times 10^9\ Hz$

Explanation:

Given that,

A system can detect objects as small as 19.1 cm i.e. 0.191 m. It is the wavelength.

We know that,

Frequency, $f=\dfrac{c}{\lambda}$

So,

$f=\dfrac{3\times 10^8}{0.191}\\\\=1.57\times 10^9\ Hz$

So, the frequency of such a system is equal to $1.57\times 10^9\ Hz$ .

4 0

3 years ago

The energy transformation a leaf on a tree undergoes when sunlight shines on it is an example of what?

Damm [24]

Answer:Radiant to chemical

Explanation:

6 0

4 years ago