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kondor19780726 [428]
3 years ago
9

The energy transformation a leaf on a tree undergoes when sunlight shines on it is an example of what?

Physics
1 answer:
Damm [24]3 years ago
6 0

Answer:Radiant to chemical

Explanation:

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Elizabeth, with a mass of 56.1kg stands on a scale in an elevator. Total mass of elevator plus Elizabeth=850kg. As the elevator
Reil [10]

Answer:

acceleration = 1.79 m/s^2

Tension = 6817 N

Explanation:

First let's find Elizabeth's weight:

P = m*g = 56.1 * 9.81 =  550.34\ N

Her weight is greater than the normal force (N = 450 N), so the elevator is going downwards.

The acceleration of Elizabeth is given by:

P - N = m*a

Where P is the weight of Elisabeth, N is her normal force, m is her mass and a is the acceleration. Then, we have that:

56.1*9.81 - 450 = 56.1*a

a = 100.34 / 56.1 = 1.79\ m/s^2

The tension in the cable is given by:

P - T = m*a

In this case, we use the total mass, so we have:

850*9.81 - T = 850*1.79

T = 850 * 8.02 = 6817\ N

7 0
3 years ago
Microwelds are formed where_______
Shtirlitz [24]
The correct answer is B
5 0
3 years ago
Read 2 more answers
What is the amplitude and wavelength of the wave shown below?
masha68 [24]

Answer:

Option B

Explanation:

I did a question like this a long time ago so i'm not sure if its right so sorry if its wrong

3 0
3 years ago
g Suppose that you charge a 3 F capacitor in a circuit containing eight 3.0 V batteries, so the final potential difference acros
Vladimir79 [104]

The complex, highly technical formula for capacitors is

<em>Q = C V</em>

Charge = (capacitance) (voltage)

Charge = (3 F) (24 V)

<em>Charge = 72 Coulombs</em>

The positive plate of the capacitor is missing 72 coulombs worth of electrons.  They were sucked into positive terminal of the battery stack.

The negative plate of the capacitor has 72 coulombs worth of extra electrons.  They came from the negative terminal of the battery stack.

You should be aware that this is a humongous amount of charge !  An average <u><em>lightning bolt</em></u>, where electrons flow between a cloud and the ground for a short time, is estimated to transfer around <u><em>15 coulombs</em></u> of charge !

The scenario in the question involves a "supercapacitor".  3 F is is no ordinary component ... One distributor I checked lists one of these that's able to stand 24 volts on it, but that product costs $35 apiece, you have to order at least 100 of them at a time, and they take 2 weeks to get.  

Also, IF you can charge this animal to 24 volts, it will hold 864J of energy.  You'd probably have a hard time accomplishing this task with a bag of leftover AA batteries.

7 0
3 years ago
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.50 mm. A 25
torisob [31]

Answer:

The electric field is 16666.66 V/m.

The surface charge density is 1.474\times10^{-7}\ C/m^2

The capacitance is 4.484\times10^{-12}\ F

The charge on each plate is 112.1\times10^{-12}\ C

Explanation:

Given that,

Area =7.70 cm²

Distance = 1.50 mm

Potential difference = 25.0 V

Suppose  we find the electric field between the plates, the surface charge density, the capacitance and the charge on each plates.

We need to calculate the electric field

Using formula of electric field

E=\dfrac{V}{d}

Put the value into the formula

E=\dfrac{25.0}{1.50\times10^{-3}}

E=16666.66\ V/m

We need to calculate the charge density

Using formula of charge density

\sigma=E\times\epsilon_{0}

Put the value into the formula

\sigma=16666.66\times8.85\times10^{-12}

\sigma=1.474\times10^{-7}\ C/m^2

We need to calculate the capacitance

Using formula of capacitance

C=\dfrac{\epsilon_{0}A}{d}

Put the value into the formula

C=\dfrac{8.85\times10^{-12}\times7.60\times10^{-4}}{1.50\times10^{-3}}

C=4.484\times10^{-12}\ F

We need to calculate the charge

Using formula of charge

q=CV

Put the value into the formula

q=4.484\times10^{-12}\times25.0

q=112.1\times10^{-12}\ C

Hence, The electric field is 16666.66 V/m.

The surface charge density is 1.474\times10^{-7}\ C/m^2

The capacitance is 4.484\times10^{-12}\ F

The charge on each plate is 112.1\times10^{-12}\ C

8 0
3 years ago
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