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erik [133]
3 years ago
13

202 divided by 3 with a remaining number

Mathematics
2 answers:
svlad2 [7]3 years ago
7 0

Answer:

67 R \frac{1}{3}  

I hope this helps!

densk [106]3 years ago
5 0

Answer:

67\frac{1}{3} or 67.33333333333333...

Step-by-step explanation:

Hope this helped! :)

P.S. The last 3 is going on forever, I don't know how to make that line above it though.

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A arcade game gives 8 tickets ,y, for every 5 games played,x.
Ray Of Light [21]

Answer:

5,8 or 8,5

Step-by-step explanation:

A arcade game gives 8 tickets this = y

For every 5 game played this = x

so we can make the assumption that every 5 games played he gets 8 tickets you can write this as 5,8 or. Every 5 game played is 8 tickets.

7 0
3 years ago
The perimeter of a rectangular painting is 262 centimeters. If the width of the painting is 59 centimeters, what is its length?
Liula [17]
The formula of the perimeter of a rectangle is 2l+2w so look at the photo
3 0
3 years ago
Celeste needs to create a keyword map that branches out from an image of the solar system. Which image best
Veseljchak [2.6K]

Answer:

The Correct Answer Is C

Step-by-step explanation:

4 0
3 years ago
Find an expression for the nth term -3 , 2 , 7, 12​
slavikrds [6]

Answer:

5n-8

Step-by-step explanation:

Because this is an arithmetic progression, there is simply an addend that is being added to every number. Because that is 5, the expression, for now, would be 5n. However, the progression does not start at 0, so we will have to subtract 3, and then it would be 5n - 3. We're still not at the answer; this is because the first term starts at 1, not 0. We will have to account for that, so subtract the coefficient, or 5, from the whole expression. That would be 5n - 8, and that would be the answer.

4 0
3 years ago
In Exercise,find the horizontal asymptote of the graph of the function.<br> f(x) = 8x^3+2/2x^3+x
KIM [24]

Answer:

Horizontal asymptote of the graph of the function f(x) = (8x^3+2)/(2x^3+x) is at  y=4

Step-by-step explanation:

I attached the graph of the function.

Graphically, it can be seen that the horizontal asymptote of the graph of the function is at y=4. There is also a <em>vertical </em>asymptote at x=0

When denominator's degree (3) is the same as the nominator's degree (3) then the horizontal asymptote is at (numerator's leading coefficient (8) divided by denominator's lading coefficient (2))  y=\frac{8}{2}=4

6 0
3 years ago
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