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3 years ago

Need Help!!!!!!!!!!!!!

Mathematics

1 answer:

zepelin [54]3 years ago

3 0

the thing to do here is multiply base and height in this case 2yd and 2.3yd, that's how I would solve it.

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The sum of two numbers is 24 and their difference is . what are the numbers

Darina [25.2K]

X + y = 24
x - y = 2
-------------add
2x = 26
x = 26/2
x = 13

x - y = 2
13 - y = 2
-y = 2 - 13
-y = - 11
y = 11

ur numbers are 11 and 13

7 0

4 years ago

Read 2 more answers

Basic inequality need help

Natalka [10]

Number 7 is probably 4 because x is on the top which means it’s greater than 7

6 0

3 years ago

X = -y-6<br> 7x + 6y = –10

Ede4ka [16]

Answer:

[26, -32]

Step-by-step explanation:

7[-y - 6] + 6y = -10

-7y - 42 + 6y = -10

-y - 42 = -10

+ 42 + 42

____________

-y = 32

-32 = y [Plug this back into both equations to get the x-value of 26]; 26 = x

I am joyous to assist you anytime.

7 0

3 years ago

F and H are sets of real numbers defined as follows.

Marina CMI [18]

Answer:

$(a)F \cup H=(3, \infty)\\(b)F \cap H=(6, \infty)$

Step-by-step explanation:

Given the sets F and H of real numbers defined as given:

F={w | w>3}

H={w | w>6}

To write a set in interval notation, we use these brackets, ( ) for < or > while we use [ or ] for $\leq $ or \geq$ .

Since our sets are defined by strict inequalities(< or >)

In interval notation

$F=(3,\infty), H=(6,\infty)$

$(a) F \cup H =(3,\infty) \cup (6,\infty) \\\\F \cup H=(3, \infty)\\\\(b) F \cap H =(3,\infty) \cap (6,\infty) \\\\F \cap H=(6, \infty)$

8 0

3 years ago

Please help meeeeeeeeeeeeeeeeeee

miskamm [114]

Answer:

$\frac{3^{12}}{3^{10}}$

Step-by-step explanation:

+ or x you plus the indices

- or divide you minus the indices

so 3^8 x 3^4 would be 3^12

and 3^2 x 3^8 would be 3 ^10

7 0

3 years ago