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4 years ago

Listed following are locations and times atwhich different phases of the Moon are visible fromEarth’s....?

Physics

1 answer:

ad-work [718]4 years ago

5 0

Answer:

Explanation:

*visible near western horizon an hour aftersunset WAXING CRESCENT

*rises about the same time the sun sets FULLMOON

*visible near eastern horizon just before sun rises WANING CRESCENT

*occurs about 3 days before new moon WANING CRESCENT

*visible due south at midnite FULL MOON

*occurs 14 days after new moon FULL MOON

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Musicians can use beats to tune their instruments. One flute is properly tuned and plays the musical note A at exactly 440 Hz. A

kodGreya [7K]

Answer:

439 Hz

Explanation:

$f_1$ = Frequency of first wave = 440 Hz

F = Beat frequency = 1 Hz

$f_2$ = Frequency of the instrument

The beat frequency is the difference of the two waves which are interacting with each other

$F=f_1-f_2\\\Rightarrow 1=440-f_2\\\Rightarrow f_2=440-1\\\Rightarrow f_2=439\ Hz$

The frequency of the instrument is 439 Hz

5 0

3 years ago

A ball is thrown straight up from ground level. It passes a 2-m-high window. The bottom of the window is 7.5 m off the ground. T

slamgirl [31]

Answer:

$u=14.48m/s$

Explanation:

From the question we are told that:

Height of window $h=2m$

Height of window off the ground $h_g=7.5m$

Time to fall and drop $t=1.3s$

Generally the Newton's equation motion is mathematically given by

$s=ut+\frac{1}{2}at^2$

Where

$h=ut+\frac{1}{2}at^2$

$2=u1.3-\frac{1}{2}*9.8*1.3^2$

$2=u1.3-8.281$

$u=7.91m/s^2$

Generally the Newton's equation motion is mathematically given by

$2as=v^2-u^2$

Where

$-2gh_g=v^2-u^2$

$-2*9.8*7.5=(7.91)^2-u^2$

$-147=62.5681-u^2$

$u=\sqrt{209.5681}$

$u=14.48m/s$

Therefore the ball’s initial speed

$u=14.48m/s$

8 0

3 years ago

2.5 years into minutes?<br><br>

Mnenie [13.5K]

Is it 1314000 Or something

8 0

3 years ago

A box slides down a ramp inclined at 24◦ to the horizontal with an acceleration of 1.7 m/s 2 . The acceleration of gravity is 9.

dsp73

Answer:

Explanation:

In friction, the coefficient of friction formula is expressed as;

$\mu = \frac{F_f}{R}$

Ff is the frictional force = Wsinθ

R is the reaction = Wcosθ

Substitute inti the equation;

$\mu = \frac{Wsin \theta}{W cos\theta} \\\mu = \frac{sin \theta}{cos\theta} \\\mu = tan \theta$

Given

θ = 24°

$\mu = tan 24^0\\\mu = 0.445\\$

Hence the coefficient of kinetic friction between the box and the ramp is 0.445

3 0

3 years ago

Why can light travel through outer space, but sound cannot?

WINSTONCH [101]

Usually, sound needs a medium to travel through, like a vacuum for example.

Light does not need a medium to travel, and since air is considered a medium, light is not dependent on that.

On the other hand, sound needs a medium to travel through, and outer space doesn't contain space, therefore, no sound.

5 0

4 years ago

Read 2 more answers