The temperature will increase
Answer:
Friction is when a force is applied or done by weight dragging onto something.
Explanation:
Gravity is when an object is getting pulled toward the center of what is attracting it. And applied force is when someone/sommething is applying force.
Answer:
The current of the solenoid is 0.0129 A.
Explanation:
The movement of the electron within the solenoid in a circle is produced by equaling the magnetic force and the centripetal force, as follows:


Where:
I: is the current
m: is the electron's mass = 9.1x10⁺³¹ kg
v: is the electron's speed = 3.0x10⁵ m/s
μ₀: is the permeability magnetic = 4πx10⁻⁷ T.m/A
n: is the number of turns per unit length = 35/cm
r: is the radius of the circle = 3.0 cm
e: is the electron's charge = 1.6x10⁻¹⁹ C
Therefore, the current of the solenoid is 0.0129 A.
I hope it helps you!
Answer:
The electron’s velocity is 0.9999 c m/s.
Explanation:
Given that,
Rest mass energy of muon = 105.7 MeV
We know the rest mass of electron = 0.511 Mev
We need to calculate the value of γ
Using formula of energy


Put the value into the formula


We need to calculate the electron’s velocity
Using formula of velocity




Put the value into the formula



Hence, The electron’s velocity is 0.9999 c m/s.