The chart lists the masses and velocities of four objects.
Which object requires the greatest change in momentum in order to stop its motion?
Answer
Z
Answer:
A is the answer
Explanation:
That's why it ranges from big to small.
Answer:
v = 15.8 m/s
Explanation:
Let's analyze the situation a little, we have a compressed spring so it has an elastic energy that will become part kinetic energy and a potential part for the man to get out of the barrel, in addition there is a friction force that they perform work against the movement. So the variation of mechanical energy is equal to the work of the fictional force
= ΔEm =
-Em₀
Let's write the mechanical energy at each point
Initial
Em₀ = Ke = ½ k x²
Final
= K + U = ½ m v² + mg y
Let's use Hooke's law to find compression
F = - k x
x = -F / k
x = 4400/1100
x = - 4 m
Let's write the energy equation
fr d = ½ m v² + mgy - ½ k x²
Let's clear the speed
v² = (fr d + ½ kx² - mg y) 2 / m
v² = (40 4.00 + ½ 1100 4² - 60.0 9.8 2.50) 2/60.0
v² = (160 + 8800 - 1470) / 30
v = √ (229.66)
v = 15.8 m/s
Answer:
w'=(1/2)w
Explanation:
In order to calculate the angular velocity of the second wheel, you use the following formula:
(1)
v: speed of the wheel 1 = speed of the wheel 2
r: radius of the wheel 1
For the second wheel you have:
r'=2r
You replace this value of r' in the following equation:

The angular velocity of the second wheel is one half of the angular velocity of the first wheel
The speed he was moving at when he finished falling is 30 m/s.
The given parameters;
mass of the bungee, m = 80 kg
impulse provided by the rope, J = 3200 Ns
initial upward velocity of the jumper, u = 10 m/s
- Let the final velocity after falling = v
- Let the upwards motion = negative
- Let the downwards motion when falling = positive
Apply the principle of conservation of linear momentum;
J = ΔP = Δmv = m(v - u)
3200 = 80(v - (-10))
3200 = 80(v + 10)

Thus, the speed he was moving at when he finished falling is 30 m/s.
Learn more here:brainly.com/question/19027317