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Sophie [7]
3 years ago
12

Number 2

Mathematics
2 answers:
Andrej [43]3 years ago
8 0
2. A ) yes they form a line together
B) No they do not form a straight line
C) Yes are formed by the intersection of two straight lines
D) No
klemol [59]3 years ago
5 0
A. Yes, they make a 180° line
B. No, they do not make a 180° line
C. Yes, they are the same angle measurment, but across from each other
D. No. they are not the same angle measurment
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-26 is the answer :)

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What is the percent of change in the cost of a hot dog?
gtnhenbr [62]

Answer:

What hotdogs

Give the numbers

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Carlos earns $3.50 a day on his paper route. He runs
loris [4]

Answer:

their are 4 weeks in a month so 4*7=

28

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Hope This Helps!!!

6 0
2 years ago
Read 2 more answers
x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
What is the perimeter of this tile 4in. 1in.? is it 10 in. or 10 in2power
coldgirl [10]

 

P = 2 × 4in + 2 × 1in = 8in + 2in = 10in

<h2><u>P = 10 in</u></h2>

 

 

3 0
3 years ago
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