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DerKrebs [107]
3 years ago
5

6-8x=23 What number is x

Mathematics
2 answers:
Vikki [24]3 years ago
7 0
X = -17/8

Do you need explanation?
aleksley [76]3 years ago
3 0

Answer:

x= -2.1

Step-by-step explanation:

6-8x=23

-6 -6

-8x=17

-8 -8

x= -2.1

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3 years ago
2x+3x=15 and x+y=6 what is x and y
gulaghasi [49]

Answer: x=3 y=3

Step-by-step explanation:

Assuming you meant 2x+3y=15 as the first problem. You have to make either both the x’s or both the y’all equal in both equations first. Multiply the second equation by 2 (for x’s) and you’ll get 2x+2y=12. The 2x cancels out so you’re left with 3y=15 and 2y=12. Subtract 2y=12 from 3y=15 and you get y=3.

Repeat to figure out x. Multiple second equation by 3 (for equal y’s) and you get 3x+3y=18. This time the first equation is being subtracted from the second one. (3x+3y=18) - (2x+3y=15). Y’s cancel out and you’re left with (3x=18)-(2x=15. Subtract and you get x=3

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bm%7D%20%20%3D%20n%20" id="TexFormula1" title=" {2}^{m} = n " alt=" {2}^{m} =
sveta [45]

Answer:

\displaystyle n^3-\frac{1}{n^{2}}

Step-by-step explanation:

<u>Exponents Properties</u>

We need to recall the following properties of exponents:

(a^x)^y=(a^y)^x=a^{xy}

\displaystyle a^{-x}=\frac{1}{a^x}

We are given the expression:

2^m=n

We need to express the following expression in terms of n.

8^m-4^{-m}

It's necessary to modify the expression to use the given equivalence.

Recall 8=2^3 \text{ and }4 = 2^2. Thus:

(2^3)^m-(2^2)^{-m}

Applying the property:

(2^m)^3-(2^m)^{-2}

Substituting the given expression:

n^3-n^{-2}

Or, equivalently:

\mathbf{\displaystyle 8^m-4^{-m}= n^3-\frac{1}{n^{2}}}

5 0
3 years ago
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