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Alika [10]
3 years ago
15

Please help me, worth LOTS of points

Mathematics
1 answer:
Aliun [14]3 years ago
4 0

Answer:

a) 91\,+\,0.14 \,x \leq 140   where "x" stands for the number of miles driven.

b) He can drive as far as 250 miles to keep the rental cost limited to $140.

Step-by-step explanation:

a) Robert wants to make sure that the addition of the costs coming from the car rental per week ($91) plus the amount paid for the coverage of "x" number of miles (which goes as $0.14 times x) does not exceed $140 (which is the same as saying that this total cost must be smaller than or equal to $140.

In math terms, such is written as:

91\,+\,0.14 \,x \leq 140

where "x" stands for the number of miles driven.

b) the total number of miles (x) he is allowed to cover given the $140 restriction is obtained by solving for "x" (the number of driven miles) in the inequality of part a):

91\,+\,0.14 \,x \leq 140\\0.14\,x\leq 140-91\\0.14\,x\leq 49\\x\leq \frac{49}{0.14} \\x\leq 350

which tells us that the number of driven miles (x) has to be smaller or equal to 350 miles. Then he can drive as far as 250 miles to keep the rental cost limited to $140.

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Use the data from problem:
navik [9.2K]

Answer:

a) Sample mean: 48.71

Sample median: 48.3

Sample variance: 5.41

Sample standard deviation: 2.37

Step-by-step explanation:

a) Sample mean:

\bar{X}=\frac{1}{N} \sum X_i=\frac{1}{80}*3896.9=48.71

Sample median: M=48.3

Note: I order the data increasingly and take the value N / 2 = 40. In this way there are 39 values above and 39 values below the median.

Sample variance:

s^2=\frac{1}{N-1}\sum (X_i-\bar X)^2 =(\frac{1}{80-1})*427.74=5.41

Sample standard deviation

s=\sqrt{s^2}=\sqrt{5.41}=2.37

b)

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3 years ago
if £2000 is placed into a bank account that pays 3% compound interest per year, how much will be in the bank account after 2 yea
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Jill's mother limited her XBOX 1 playing to 10 hours per week. She played on only four days, a different amount of time each day
Tju [1.3M]
Hello!

Let's put this down into someone of an equation. On the top of our heads we know she didn't play on Monday, Tuesday, or Thursday. This means she played on Wednesday, Friday, Saturday, and Sunday. We will use the variables w, f, s, and o, with o representing Sunday. .

s=2w
f<s
f<w
f<o
w+f+s+o=10

Since we already know what s equals, we also know that w is 1/2 of the time played on Saturday. Let's try to substitute s into the last equation to see if we can find anything.

w+f+2w+o=10
3w+f+o=10

Now we just need to worry about Friday and Sunday. We know that Friday was played the least. Let's try substituting 2w for s in one the equations.

f<2w

This means that f cannot be 2w. But it also cannot be w either, since all of the times were different. It has to be less than w. Perhaps we could try using 0.5w in our equation and see if it would all add up to 10

3.5w+o=10

Given that there are no partial hours, w has to equal 2, because if we did 1, then o would be partial, and if we did 3 it would be more than ten. Now that we have the value of w we can find all of the numbers.

s=2(2)
s=4

Now we have four hours left. We can only split this up in one way, 3 and 1, since 2 and 2 are the same and all of the times are different. Since we know Friday is the least, we know that f=1, and that leaves o=3.

Wednesday: 2 hours
Friday: 1 hour
Saturday: 4 hours
Sunday :3 hours

I hope this helps!

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