Answer:
m∠BCE = 28° and m∠ECD = 134°
Step-by-step explanation:
* Lets explain how to solve the problem
- The figure has three angles: ∠BCE , ∠ECD , and ∠BCD
- m∠ECD is six less than five times m∠BCE
- That means when we multiply measure of angle BCE by five and
then subtract six from this product the answer will be the measure
of angle ECD
∴ m∠ECD = 5 m∠BCE - 6 ⇒ (1)
∵ m∠BCD = m∠BCE + m∠ECD
∵ m∠BCD = 162°
∴ m∠BCE + m∠ECD = 162 ⇒ (2)
- Substitute equation (1) in equation (2) to replace angle ECD by
angle BCE
∴ m∠BCE + (5 m∠BCE - 6) = 162
- Add the like terms
∴ 6 m∠BCE - 6 = 162
- Add 6 to both sides
∴ 6 m∠BCE = 168
- Divide both sides by 6
∴ m∠BCE = 28°
- Substitute the measure of angle BCE in equation (1) to find the
measure of angle ECD
∵ m∠ECD = 5 m∠BCE - 6
∵ m∠BCE = 28°
∴ m∠ECD = 5(28) - 6 = 140 - 6 = 134°
* m∠BCE = 28° and m∠ECD = 134°
52 ×.65= X
The answer would be $80. Hope i could be helpful :)
The formula of a function is the rise over run.
The slope would be 2/5.
Hope this helps!
The child is <u>59.4 inches tall</u>, assuming the length from the coach's shoulder to his head cap is approximately 10 inches.
<h3>What is Heigth?</h3>
Height refers to the vertical distance between the top and bottom of something.
Height measures the length of some objects or persons vertically to determine whether it is high or low, according to some ascertained criteria.
<h3>Data and Calculations:</h3>
Baseball coach's height = 70 inches
Coach's shoulder to head = 10.6 inches
Height of the child standing slightly below the coach's shoulder = 59.4 inches (70 - 10.6)
Thus, the child standing slightly below the coach's shoulder is 59.4 inches tall.
Learn more about height measurements at brainly.com/question/73194
#SPJ1
<h3>Question Completion:</h3>
Assume that the height of the coach from his shoulder to the head is 10.6 inches.
Answer:
-3, 2
Step-by-step explanation:
