The length of a spring varies directly with the mass of an object that is attached to it. When a 30-gram object is attached, the

Question

Lisa [10]

3 years ago

11

The length of a spring varies directly with the mass of an object that is attached to it. When a 30-gram object is attached, the

spring stretches 9 centimeters. Which equation relates the mass of the object, m, and the length of the spring, s?

Mathematics

2 answers:

Rom4ik [11] · Answer 1 · 2021-12-18T13:59:28+03:00

Rom4ik [11]3 years ago

8 0

M/s=30/9 =10/3

so, 3m=10s

Scrat [10] · Answer 2 · 2021-12-18T16:28:23+03:00

Answer:

s = (3 cm)/(10 g)*m

Step-by-step explanation:

The length of a spring varies directly with the mass means that the equation has the next form: s = k*m, where m refers to the mass of the object and s refers to the length of the spring. If a 30-gram object is attached, the spring stretches 9 centimeters, then:

s = k*m

9 cm = k*30 g

(9 cm)/(30 g) = k

(3 cm)/(10 g) = k

Therefore, the equation is s = (3 cm)/(10 g)*m