The average force on the squid during the ejection of 0.60 kg of water at a velocity of 15.0 m/s in 0.15 seconds is 60 N.
We can calculate the average force with the average acceleration as follows:
(1)
Where:
- m: is the mass of water = 0.60 kg
: is the average acceleration
The <em>average acceleration</em> is given by the change of velocity in an interval of time
(2)
Where:
: is the initial velocity = 0 (the squid is at rest)
: is the final velocity = 15.0 m/s
: is the initial time = 0
: is the final time = 0.15 s
Now we can find the <em>average force</em> after entering equation (2) into (1)
Therefore, the average force on the squid during the propulsion is 60 N.
Find more about average force here:
I hope it helps you!
The JWST is postioned about 1.5 million kilometers from the earth on the side facing away from the sun
Answer:
The near point of an eye with power of +2 dopters, u' = - 50 cm
Given:
Power of a contact lens, P = +2.0 diopters
Solution:
To calculate the near point, we need to find the focal length of the lens which is given by:
Power, P = 
where
f = focal length
Thus
f = 
f = 
= + 0.5 m
The near point of the eye is the point distant such that the image formed at this point can be seen clearly by the eye.
Now, by using lens maker formula:
where
u = object distance = 25 cm = 0.25 m = near point of a normal eye
u' = image distance
Now,
Solving the above eqn, we get:
u' = - 0.5 m = - 50 cm
Answer:
Planets were like gods.
Explanation:
To the people of many ancient civilizations, the planets were thought to be deities. Our names for the planets are the Roman names for these deities. For example, Mars was the god of war and Venus the goddess of love.
Answer:
5.7141 m
Explanation:
Here the potential and kinetic energy will balance each other
This is the initial velocity of the system and the final velocity is 0
t = Time taken = 0.04 seconds
F = Force = 18000 N
a = Acceleration
g = Acceleration due to gravity = 9.81 m/s²
Equation of motion
From Newton's second law
Squarring both sides
The height from which the student fell is 5.7141 m
