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4 years ago

Discuss how metallic bonding accounts for the common properties of metals

1 answer:

8 0

Metals are goods conductors of electricity because the electrons in the electrons sea are free to flow and carry electric currents. Metals are ductile and malleable because local bonds can be easily broken and reformed.

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A wave which needs a medium (solid, liquid, gas) in order to propagate itself.

Vadim26 [7]

The correct answer to the question is: Sound wave.

EXPLANATION:

Before going to answer this question, first we have to understand longitudinal wave.

A longitudinal wave is a mechanical wave in which the direction of propagation of wave is parallel to the direction of particle vibration.

This wave propagates through a medium in the form of compression and rarefaction.

Compression are the regions of high pressure zones where the particles of the medium are closely aggregated to each other.

Rarefaction is the region of low pressure where particles of the medium are not so close to each other as compared to compression.

The longitudinal wave can not propagate in space. It always needs a medium for it's propagation. The medium may be solid, liquid or gas .

For instance, sound wave is a longitudinal wave.

Hence, the correct answer of this question is sound wave which needs a medium for it's propagation.

5 0

3 years ago

Read 2 more answers

Calculate the amount of heat needed to raise the temperature of 200g of ice from-30°C 50C water. (C = .5 for ice, C 1 for water,

Nitella [24]

Answer: The amount of heat needed is 29000 Cal.

Explanation:

The process involved in this problem are:

$(1):H_2O(s)(-30^oC)\rightarrow H_2O(s)(0^oC)\\\\(2):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(3):H_2O(l)(0^oC)\rightarrow H_2O(l)(50^oC)$

Now, we calculate the amount of heat released or absorbed in all the processes.

For process 1:

$q_1=mC_{p,s}\times (T_2-T_1)$

where,

$q_1$ = amount of heat absorbed = ?

m = mass of ice = 200 g

$T_2$ = final temperature = $0^oC$

$T_1$ = initial temperature = $-30^oC$

Putting all the values in above equation, we get:

$q_1=200g\times 0.5Cal/g^oC\times (0-(-30))^oC=3000Cal$

For process 2:

$q_2=m\times L_f$

where,

$q_1$ = amount of heat absorbed = ?

m = mass of water or ice = 200 g

$L_f$ = latent heat of fusion = 80 Cal/g

Putting all the values in above equation, we get:

$q_2=200g\times 80Cal/g=16000Cal$

For process 3:

$q_3=m\times C_{p,l}\times (T_{2}-T_{1})$

where,

$q_3$ = amount of heat absorbed = ?

m = mass of water = 200 g

$T_2$ = final temperature = $50^oC$

$T_1$ = initial temperature = $0^oC$

Putting all the values in above equation, we get:

$q_3=200g\times 1Cal/g^oC\times (50-0)^oC=10000Cal$

Calculating the total heat absorbed, we get:

$Q=q_1+q_2+q_3$

$Q=3000+16000+10000=29000Cal$

Hence, the amount of heat needed is 29000 Cal.

7 0

4 years ago

What happens to the Connecticut Energy of a snowball as it rolls across the lawn and gains mass?

statuscvo [17]

I think it will go down like decrease minus or whatever you call it

6 0

4 years ago

A stiff wire 44.0 cm long is bent at a right angle in the middle. One section lies along the z axis and the other is along the l

Helga [31]

The magnitude of force acting on wire will be 1.90 N and the direction of the force acting on the wire will be 41.9 degrees below the negative y axis.

Explanation:

It is known that the force acting on a current carrying conductor placed in a magnetic field is

$F=BIL sin theta$

Here B is the magnetic field, I is the current flowing through the wire and L is the length of the wire which is given as 44 cm.

Since the wire is bended in the middle at right angle so the length of the two sides of the wire will be 22 cm each. Also one part is lying over z axis and another part lies in the plane of xy in the equation of line y = 2x. So the slope of this wire will be

$\frac{y}{x} =2$

This will be equal to tan θ.

So θ = tan⁻¹ (2) =63.4°

Then, the length of the wire will be written as components of i, j and k.

$L = (-22)k+(22) cos ( 63.4) i+(22) sin (63.4)j$

$L = 0.098 i+0.197 j-0.22k$

Then,

F = I (L × B)

$F = 20.5 ((0.0985 i + 0.197 j -0.22k) * (0.316 i))$

$F = 20.5 (\left[\begin{array}{ccc}i&j&k\\0.098&0.197&-0.22\\0.316&0&0\end{array}\right] )$

$F = 20.5(i(0)-j(0-(-0.22*0.316))+k(0-(0.316*0.197))) = 20.5(-0.069 j-0.062 k)$

$F = -1.415 j-1.271 k$

The magnitude of force on the wire will be

$F = \sqrt{(-1.415)^{2}+(-1.27)^{2} } = \sqrt{3.615}=1.90 N$

And the direction can be found by the tan inverse of the ratio of k component to j component of the force.

$theta = tan-1(\frac{-1.271}{-1.415})= 41.9 degrees$

So the magnitude of force acting on wire will be 1.90 N and the direction of the force acting on the wire will be 41.9 degrees below the negative y axis.

5 0

4 years ago

A skier starts from rest and accelerates down a slope 2 at 23 m/s^2. How much time required for the skier to reach a speed of 9.

gayaneshka [121]

The skier's speed at time t is

v = (23 m/s²) t

To reach a speed of 9.3 m/s, the skier would need

9.3 m/s = (23 m/s²) t

t = (9.3 m/s) / (23 m/s²)

t ≈ 0.404 s

6 0

3 years ago