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Y_Kistochka [10]
3 years ago
7

4+2p=10(3/5p-2) solve for P Give an exact answer

Mathematics
2 answers:
valentinak56 [21]3 years ago
8 0

Answer:

p=6

Step-by-step explanation:

Contact [7]3 years ago
4 0

Simplify 3/5p tp 3p/5

4 + 2p = 10(3p/5 - 2)

Expand

4 + 2p = 6p - 20

Subtract 2p from both sides

4 = 6p - 20 - 2p

Simplify 6p - 20 - 2p to 4p - 20

4 = 4p - 20

Add 20 to both sides

4 + 20 = 4p

Simplify 4 + 20 tp 24

24 = 4p

Divide both sides by 4

24/4 = p

Simplify 24/4 to 6

6 = p

Switch sides

<u>p = 6</u>

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it cost $35 for one adult and two children to attend a show. It cost $60 for two adults and three children to attend the same sh
N76 [4]
Assume that,
adult = x
child = y

x+2y = 35 (1st equation)
2x+3y = 60 (2nd equation)
x = 35-2y (3rd equation)

Substitute 3 into 2 :

2(35-2y) + 3y =60
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7 0
3 years ago
Amanda spent a total of 70 minutes competing her chores this week. Write and solve an equation to represent the number of minute
gtnhenbr [62]

Answer:

28 minutes spent in washing the dishes.

Step-by-step explanation:

Given the table

Chore             time in minutes

Sweeping           42

Dishes                  ?

Amanda spent a total of 70 minutes competing her chores this week

Total of 70 minutes spent

42 minutes spent in sweeping . to find the number of minutes Amanda spent in washing the dishes , subtract 42 minutes from the total time spent

let x be the number of minutes spent washing the dishes

42+x=70

To solve for x , subtract 42 from both sides

42+x=70\\x= 70-42\\x=28

28 minutes spent in washing the dishes.

4 0
3 years ago
When two lines have the same slope they are parallel. using this statement, decide whether the two lines below are parallel or n
bearhunter [10]

Answer:

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4 0
3 years ago
Solve the following question
White raven [17]

Answer:

g) u^{4}\cdot v^{-1}\cdot z^{3}, h) \frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}

Step-by-step explanation:

We proceed to solve each equation by algebraic means:

g) \frac{u^{5}\cdot v}{z}\div  \frac{u\cdot v^{2}}{z^{4}}

1) \frac{u^{5}\cdot v}{z}\div  \frac{u\cdot v^{2}}{z^{4}} Given

2) \frac{\frac{u^{5}\cdot v}{z} }{\frac{u\cdot v^{2}}{z^{4}} } Definition of division

3) \frac{u^{5}\cdot v\cdot z^{4}}{u\cdot v^{2}\cdot z}   \frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}

4) \left(\frac{u^{5}}{u} \right)\cdot \left(\frac{v}{v^{2}} \right)\cdot \left(\frac{z^{4}}{z} \right)  Associative property

5) u^{4}\cdot v^{-1}\cdot z^{3}   \frac{a^{m}}{a^{n}} = a^{m-n}/Result

h) \frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10}

1) \frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10} Given

2) \frac{\frac{x^{2}-16}{x^{2}-10\cdot x+25} }{\frac{3\cdot x - 12}{x^{2}-3\cdot x - 10} } Definition of division

3) \frac{(x^{2}-16)\cdot (x^{2}-3\cdot x -10)}{(x^{2}-10\cdot x + 25)\cdot (3\cdot x - 12)}  \frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}

4) \frac{(x+4)\cdot (x-4)\cdot (x-5)\cdot (x+2)}{3\cdot (x-5)^{2}\cdot (x-4) } Factorization/Distributive property

5) \left(\frac{1}{3} \right)\cdot (x+4)\cdot (x+2)\cdot \left(\frac{x-4}{x-4} \right)\cdot \left[\frac{x-5}{(x-5)^{2}} \right] Modulative and commutative properties/Associative property

6) \frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}  \frac{a^{m}}{a^{n}} = a^{m-n}/\frac{a}{b}\times \frac{c}{d} = \frac{a\cdot c}{b\cdot d}/Definition of division/Result

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