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Answer:
\[y = (-1/2) * x + 6\]
Step-by-step explanation:
Equation of the given line: y=2x+2
Hence the slope of the line is given by 2
Any line which is perpendicular to the given line will have a slope m such that m*2 = -1
Or, \[m = \frac{-1}{2}\]
Only options 2 and 3 satisfy this condition.
The line is also supposed to pass through the point (6,3).
Substituting these values in the option 2:
\[3 = (-1/2) * 6 + 3\]
Or, \[ 3 =0 \] which is false . Hence option 2 is not valid.
Now substituting (6,3) in option 3:
\[3 = (-1/2) * 6 + 6\]
Or, \[ 3 =3 \] which is true . Hence option 3 is the required equation of the line.
the Highest common factor of 130,260,390 = 130
130 = 2⋅5⋅13
260 = 2⋅2⋅5⋅13
390 = 2⋅3⋅5⋅13
Common multipliers (130; 260; 390): 2, 5, 13
Now to find the highest Common factor you need to multiply the common factors
Answer: (130 ; 260 ; 390) = 2 ∙ 5 ∙ 13 = 130
