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2 years ago

What is the area of the figure

Mathematics

1 answer:

Semenov [28]2 years ago

4 0

Answer:

Area of the figure = 36 in²

Step-by-step explanation:

Area of the given composite figure = Area of the rectangle ABCE - Area of triangle CDE

Area of rectangle ABCE = Length × Width

= AB × AC

= 6 × 8

= 48 in²

Area of triangle CDE = $\frac{1}{2}(\text{Base})\times (\text{Height})$

= $\frac{1}{2}(6)(4)$

= 12 in²

Now area of the composite figure = 48 - 12

= 36 square inch

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Solve for x<br> pls show work<br> 1/2*(x - -6)= -1

Pavlova-9 [17]

Answer: x = -4

Step-by-step explanation:

1/2 * (x - (-6)) = 1

distribute

1/2x + 3 = 1

isolate the variable

1/2x = -2

x = - 4

5 0

3 years ago

Sharon and Jacob started at the same place. Jacob walked 3 m north and then 4 m west. Sharon walked 5 m south and 12 m east. How

Ilya [14]

Consider the coordinate plane:

1. The origin is the point where Sharon and Jacob started - (0,0).

2. North - positive y-direction, south - negetive y-direction.

3. East - positive x-direction, west - negative x-direction.

Then,

if Jacob walked 3 m north and then 4 m west, the point where he is now has coordinates (-4,3);
if Sharon walked 5 m south and 12 m east, the point where she is now has coordinates (12,-5).

The distance between two points with coordinates $(x_1,y_1)$ and $(x_2,y_2)$ can be calculated using formula

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}.$

Therefore, the distance between Jacob and Sharon is

$D=\sqrt{(12-(-4))^2+(-5-3)^2}=\sqrt{16^2+8^2}=\sqrt{256+64}=\sqrt{320}=8\sqrt{5}\approx 11.18\ m.$

7 0

3 years ago

Which radical expression in the picture is equivalent to t^5/8?

mixas84 [53]

<h3>Answer: Choice B</h3>

=========================================================

Explanation:

The rule we use is

$\Large a^{m/n} = \sqrt[n]{a^m} = \left(\sqrt[n]{a}\right)^m$

where 'a' is the base, m stays in the role of the exponent, and n plays the role of the root index (eg: n = 3 is a cube root, n = 4 is a fourth root, and so on).

So for instance,

$\Large 2^{3/4} = \sqrt[4]{2^3} = \left(\sqrt[4]{2}\right)^3$

or in this case,

$\Large t^{5/8} = \sqrt[8]{t^5} = \left(\sqrt[8]{t}\right)^5$

5 0

2 years ago

F(x)=(x+4) 2 −25<br><br> smaller x =<br><br> larger x = <br><br> NEED THIS ASAP

miss Akunina [59]

f(x)=(x+4) ^2 −25

to solve set equal to zero

0 =(x+4) ^2 −25

add 25 to each side

25 = (x+4) ^2

take the square root of each side

square root (25) =(x+4)

+- 5 = (x+4)

5 = x+4 -5 = x+4

subtract 4 from each side

1 =x -9 =x

3 0

3 years ago

the velocity of a car changes from 20 m/s east to 5 m/s east in 5 seconds what's the acceleration of the car

muminat

To solve this remember a=change in v/t, assuming the direction for the velocity, is + positive east. You can calculate it simply by this. A=v/t= A=5-20/5= A=-15/5= A=-3m/s squared. Change in velocity= vf-vi.

7 0

3 years ago