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2 years ago

12

A car x of mass 1000kg moves at a speed of 20m /s in direction due East collides head on with an other car Y of mass 1500kg move

s at 15m/s in a direction due west if two cars stick together find their common velocity after collision

1 answer:

igor_vitrenko [27]2 years ago

4 0

17 m /s is the common velocity after collision

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What’s 3 times 10 to the 8th power divided by 2.45 times 10 to the 9th power

Virty [35]

0.12244898 is the value obtained when solving the given.

<u>Explanation:</u>

Given:

3 times 10 to the 8th power can be expressed in equation format as $3 \times 10^{8}$ (3 times symbolizes ‘multiplication’ then it is to the tenth power of 8)

2.45 times 10 to the 9th power can be expressed in equation format as $2.45 \times 10^{9}$ (2.45 times symbolizes ‘multiplication’, then it is to the tenth power of 9)

Asked to find the solution when dividing the above,

$\frac{3 \times 10^{8}}{2.45 \times 10^{9}}=\frac{3}{2.45} \times 10^{8-9}$

When the tenth power of any value goes from denominator to numerator and vice-versa, presents in opposite sign to that it possess (like when ‘ $10^{9}$ ' goes to numerator changed as ' $10^{-9}$ ').

Now by solving the above equation, we get

$\frac{3}{2.45} \times 10^{8-9}=1.22 \times 10^{-1}=\frac{1.22}{10}=0.12244898$

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3 years ago

The term 'DENSITY' tells us…

pogonyaev

Answer:

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A racecar on a straight track, starting from rest*, steps on the

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3 years ago

A 20kg object acceleration by a force of 200N with coefficient of kineticfriction is 0.4 what is acceleration of the object?

Schach [20]

Answer:

<u>Given</u><em> </em><em>-</em><em> </em><u>M</u><u> </u><u>=</u><u> </u>20 kg

k = 0.4

F = 200 N

<u>To </u><u>find </u><u>-</u><u> </u> acceleration

<u>Solution </u><u>-</u><u> </u>

F= kMA

200 = 0.4 * 20 * acceleration

200 = 8 * a

a = 8/200

a = 0.04 m s²

<h3>a = 0.04 m s²</h3>

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1 year ago