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Semmy [17]
3 years ago
9

Suppose a scientific team is trying to recreate the energy-producing reactions tht occur in the sun.what would they need for the

experiments?
Physics
2 answers:
svet-max [94.6K]3 years ago
8 0

Answer:

<h2>A lot of hydrogen atoms, high pressure and high temperature.</h2>

Explanation:

The Sun generates energy using nuclear fusion, which is a reaction where two or more atomic nuclei are combained to form another atomic nuclei.

In this particular case, in the Sun, the energy is created by nuclear fusion of hydrogen. So, the scientific team would need a lot hydrogen atoms to from helium. Basically, the high pressure and high temperature in Sun's core makes Hydrogen nuclei to fuse, froming helium atoms.

So, basically, to recreate the energy-producing reactions inside the Sun, the scientific team would need a lot of hydrogen atoms, extremely high pressure and extremely high temperatures.

Rasek [7]3 years ago
7 0
Abundant hydrogen high temperature high pressure is that they need
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A disoriented physics professor drives 3.22 km north, then 4.75 km west, then 1.90 km south. find the magnitude and direction of
Andre45 [30]

It can be noted that the directions west and north are perpendicular to each other. hence we can use the right angle formula for calculating total distance in these directions. Also South is just negative north. This technique is called euclidean distance norm. It is the basis of Cartesian coordinate system.

Total distance = 3.22 N + 4.75 W +1.90  S

= 1.32 N + 4.75 W

D = \sqrt{N^2 + W^2}

D = 4.93 Km

direction = atan(N/W) = 15.53 deg north of west

7 0
3 years ago
A circular loop of wire with 10 turns, radius 0.241 m and resistance 0.235 Ohms is connected to a 13.1 V power supply. The magne
SVETLANKA909090 [29]

Given Information:  

Resistance of circular loop = R = 0.235 Ω 

Radius of circular loop = r = 0.241 m

Number of turns = n = 10

Voltage = V = 13.1 V

Required Information:  

Magnetic field = B = ?  

Answer:  

Magnetic field = 0.00145 T

Explanation:  

In a circular loop of wire with n number of turns and radius r and carrying a current I induces a magnetic field B

B = μ₀nI/2r

Where μ₀= 4πx10⁻⁷ is the permeability of free space  and current in the loop is given by

I = V/R

I = 13.1/0.235

I = 55.74 A

B = 4πx10⁻⁷*10*55.74/2*0.241

B = 0.00145 T

Therefore, the magnetic field at the center of this circular loop is 0.00145 T

8 0
3 years ago
Which is occurring when work is being done?
sineoko [7]

Answer:

When work is being done, the practie of labor is being performed. When work isn't being completed, this is a sign of procrastination.

Explanation:

In the answer.

5 0
3 years ago
Read 2 more answers
A population is comprised of all one species, whereas a ___________ is made up of many of these.
miv72 [106K]

Answer: Ecosystem

Explained: There's a minimum word count I'm filling up, don't mind me.

5 0
3 years ago
A point charge is placed at each corner of square with side leanth a. The charges all have same magnitude q. My question, What i
nexus9112 [7]

Answer:

 E = k q / a²   (1.3535) (- i ^ + j ^)

  E = k q / a²  1.914  ,      θ’= 135

Explanation:

For this exercise we will use Newton's second law where we must add as vectors

        E_total = E₁₂ i ^ + E₁₄ j ^ + E₁₃

Let's look for the value of each term

On the x axis

       E₁₂ = k q / a²

On the y axis

       E₁₄ = k q / a²

For the charge in the opposite corner we look for the distance

        d = √ (a² + a²) = a √2

let's look for the field

      E₁₃ = k q / d²

      E₁₃ = k q / 2a²

let's use trigonometry to find the two components of this field

       cos 45 = E₁₃ₓ / E₁₃

       E₁₃ₓ = E₁₃ cos 45

       

       sin 45 = E_{13y} / E₁₃

       E_{13y} = E₁₃ sin 45

       E₁₃ₓ = k q / 2a²  cos 45

       E_{13y} = k q / 2a²  sin 45

let's find each component of the electric field

X axis

      Eₓ = -E₁₂ - E₁₃ₓ

      Eₓ = - k q / a² - k q / 2a² cos 45

      Eₓ = - k q / a² (1 + cos 45/2)

      cos 45 = sin 45 = 0.707

      Eₓ = - k q / a²   (1 + 0.707 / 2)

      Eₓ = - k q / a²    (1.3535)

Y axis  

      E_y = E₁₄ + E_{13y}

       E_y = k q / a² + k q / 2a²     sin 45

       E_y = k q / a² (1 + sin 45/2)

       E_y = k q / a²       (1.3535)

we can give the results in two ways

       E = k q / a²   (1.3535) (- i ^ + j ^)

In modulus and angle form, let's use Pythagoras' theorem for the angle

       E = √ (Eₓ² + E_y²)

        E = k q / a²    1.3535 √2

        E = k q / a²     1.914

we use trigonometry for the angle

        tan θ = E_y / Eₓ

         θ = tan⁻¹  (E_y / Eₓ)

         θ = tan⁻¹ (1 / -1)

         θ = 45

in the third quadrant, if we measure the angle of the positive side of the x-axis

           θ‘= 90 + 45

           θ’= 135

4 0
3 years ago
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