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Semmy [17]
3 years ago
9

Suppose a scientific team is trying to recreate the energy-producing reactions tht occur in the sun.what would they need for the

experiments?
Physics
2 answers:
svet-max [94.6K]3 years ago
8 0

Answer:

<h2>A lot of hydrogen atoms, high pressure and high temperature.</h2>

Explanation:

The Sun generates energy using nuclear fusion, which is a reaction where two or more atomic nuclei are combained to form another atomic nuclei.

In this particular case, in the Sun, the energy is created by nuclear fusion of hydrogen. So, the scientific team would need a lot hydrogen atoms to from helium. Basically, the high pressure and high temperature in Sun's core makes Hydrogen nuclei to fuse, froming helium atoms.

So, basically, to recreate the energy-producing reactions inside the Sun, the scientific team would need a lot of hydrogen atoms, extremely high pressure and extremely high temperatures.

Rasek [7]3 years ago
7 0
Abundant hydrogen high temperature high pressure is that they need
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Describe the climate and name the climate zone at alaska; portland, oregon; and key west, florida.
Tpy6a [65]
Alaska-                   Subartic Climate 
Portland, Oregon-  Marine West Coast Climate
Key West, Florida- Tropical Savannah Climate
3 0
3 years ago
1. An asphalt block has a mass of 90 kg and a volume of 0.075 m. Determines the density of the asphalt.
Kisachek [45]

Answer:

1. Density = 1200[kg/m^3]; 2. Volume= 0.005775[m^3], mass= 15.59[kg]

Explanation:

1. We know that the density is defined by the following expression.

Density = \frac{mass}{volume} \\where:\\mass=90[kg]\\volume=0.075[m^{3} ]\\density=\frac{90}{0.075} \\density=1200[\frac{kg}{m^{3} }]

2. First we need to convert the units to meters.

wide = 35[cm] = 35/100 = 0.35[m]

long = 11 [dm] =  11 decimeters = 11/10 = 1.1[m]

Thick = 15[mm] = 15/1000 = 0.015[m]

Now we can find the density using the expression for the density.

density= \frac{mass}{volume} \\where:\\volume = wide*long*thick\\volume=0.35*1.1*0.015 = 0.005775[m^3]\\\\mass= density*volume = 2700*0.005775 = 15.59[kg]

7 0
3 years ago
What is 1.2 kg converted into mg.<br> I need to know for step by step please?
astra-53 [7]
Here’s a good photo to reference when converting in the metric system.

Each time you move down a step you move the decimal to the right, each time you move up a step you move the decimal to the left.

We are going from 1.2 kg or kilograms, which is at the very top left of the ladder. To get to mg or milligrams, we would have to make six jumps, so we’d move the decimal over six times.

1.2 > 12. > 120. > 1200. > 12000. > 120000. > 1200000.

So our final answer would be 1,200,000mg.
4 0
3 years ago
A bus accelerates 25 m/s" and the bus has a mass of 150kg. What is the force on the bus?
o-na [289]

Answer:

150 I would believe that it is the correct answer

4 0
3 years ago
By how much do the critical angles for red (660 nm) and violet (410 nm) light differ in a diamond surrounded by air?
Stella [2.4K]

the critical angle for red light in diamond is 24.51°

critical angle for violet light in diamond is 24.01°.

given:

wavelength of red light λr =660nm

wavelength of violet light λv =410nm

refractive index for air=1

as the refractive index of red and violet colour in diamond is

Refractive index of red color nr= 2.407

Refractive index of violet color nv= 2.451

as it is mentioned that angle is critical angle,thus θr =90°

so,from Snell's law

n1sinθc=n2 sin 90°

Here,

n1 is the refractive index for incident medium

n2 is the refractive index for refractive medium

θc is the critical angle after which light starts reflecting internally

The critical angle for red light is here,n1=2.407, n2=1

n1sinθc=n2 sin 90°

2.407×sin θc=1×1

sin θc =(1/2.407)

θc=sin-1 0.415

θc=24.51°

Thus,the critical angle for red light in diamond is 24.51°

The critical angle for violet light is,

here,n1=2.451,n2=1

n1sinθc=n2 sin 90°

2.407×sin θc=1×1

sin θc= (1/2.451)

θc=sin-1 0.407

=24.01°

Thus,the critical angle for violet light in diamond is 24.01°.

learn more about Snell's law from here: brainly.com/question/2273464

#SPJ4

3 0
1 year ago
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