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Mrrafil [7]
3 years ago
5

Which planet is smaller than Earth’s core?

Physics
2 answers:
makvit [3.9K]3 years ago
7 0

Answer:

The answer <em><u>is C. Mars</u></em>. Mars and Mercury are both smaller than Earth's core. Hope this helps you :)

worty [1.4K]3 years ago
4 0

Answer:

C. Mars

Explanation:

Size of a planetary object depends on when it forms and where it forms.

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What is the energy equivalent of an object with a mass of 1.83 kg?
xxMikexx [17]
To determine the energy equivalent of an object, we use the famous equation of Einstein which is E=mc^2 where m is the mass of the object and c is the speed of light (3x10^8 m/s). We calculate as follows:

E = mc^2
E = 1.83 kg (3x10^8 m/s)^2
E = 1.647x10^17 J
6 0
3 years ago
Read 2 more answers
Newton's law of gravity was inconsistent with Einstein's special relativity because
Lubov Fominskaja [6]

Answer:

Mass and thus force depends on the reference frame chosen

Explanation:

This can be explained as Newton's law of gravity provides action which are instantaneous at a distance and involves the evaluation of all the quantities at present time or at the instant they occur.

If the body undergoes a change in its mass distribution there will be an immediate change in its gravitational force without any lag.

Now, if we talk about special relativity, it would be absurd to say that an information can travel faster than light. The effect is in synchronization with the cause in one reference frame where the effect occurs after the cause for some observer in some other reference frame.

In order to observe Newton's law of gravity all the observer's in different reference frames must observe the same phenomena which could only be possible if time were absolute and in special relativity, time is not absolute.

Therefore, Newton's law of gravity was inconsistent with the Einstein's Special Relativity.

3 0
3 years ago
If the original pressure is 5 atm and original volume is 100 L, and the new volume is 20 L, what is the new pressure?
Nana76 [90]
P1V1=P2V2
5*100=P2*20
500=20P
P=25
7 0
3 years ago
What’s the answer for this problem?
pickupchik [31]
The answer is always true a



4 0
3 years ago
A box slides down a 30.0° ramp with an acceleration of 1.20 m/s^2. Determine the coefficient of kinetic friction between the box
Zielflug [23.3K]

m = mass of the box

N = normal force on the box

f = kinetic frictional force on the box

a = acceleration of the box

μ = coefficient of kinetic friction

perpendicular to incline , force equation is given as

N = mg Cos30                                         eq-1

kinetic frictional force is given as

f = μ N

using eq-1

f = μ mg Cos30    


parallel to incline , force equation is given as

mg Sin30 - f = ma

mg Sin30 - μ mg Cos30  = ma

"m" cancel out

a = g Sin30 - μ g Cos30

inserting the values

1.20 = (9.8) Sin30 - (9.8) Cos30 μ

μ = 0.44

4 0
3 years ago
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