1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Korvikt [17]
3 years ago
5

Sound wave of a wave length of 0.56 meters if its speed is 280 m/s what is the wave frequency

Physics
1 answer:
Reika [66]3 years ago
5 0

Answer:

500 Hz

Explanation:

Formula for finding wave frequency is,

f = c/λ

f = frequency

c = speed (m/s)

λ = wave length (m)

f = c/λ

f = 280/0.56

f = 500

∴ wave frequency is 500 Hz

You might be interested in
How does regular participation in sports affect your body?
avanturin [10]

it affects your body by building/straining your muscles so you can be stronger & more athletic

6 0
3 years ago
Read 2 more answers
Define resistance and describe what would happen to a light bulb if the voltage increased but the resistance stayed the same. Re
Anarel [89]

Answer:

The light bulb would glow brighter.

Explanation:

Resistance is the opposition to current flow and in Ohm's law is represented as a constant in the equation V = IR with V the voltage, I the current and R the resistance.

Now let's assume we are in a series circuit that has only one path for electricity to follow to better explain what would happen to a light bulb if the voltage increased but the resistance stayed the same. Based on ohm's law equation, the voltage is directly proportional to the current and the resistance is constant. An increase in the voltage is therefore an increase in the current  which flows throught the light bulb making it glow brighter while a decrease in voltage results in a decrease in current flowing through the light bulb making it dim.

8 0
3 years ago
A billion years ago, Earth and its moon were just 200000 kilometers apart. Express this distance in meters.​
Luda [366]

Answer:

The  value is  x =  200000000 \  m

Explanation:

From the question we are told that

  The  distance between the earth and the moon is  d  =  200000 \  km

Generally ,

     1 \  km  =  1000 \  m

      200000 \  km \to x \  m

=>    x = \frac{200000 *  1000}{1 }

=>   x =  200000000 \  m

           

4 0
3 years ago
Is an object speeding up or slowing down of the V final is greater than the V initial?
sertanlavr [38]

Answer:

V is greater

Explanation:

because v intial at that time V final is the that speed which it is going at that time

7 0
3 years ago
Water flows through a horizontal pipe. The diameter of the pipe at point b is larger than the diameter of the pipe at point a. W
Natalija [7]

The speed of the water is the greatest at point B

5 0
4 years ago
Other questions:
  • A wave with a frequency of 0.5 Hz and a speed of 10 m/s has a wavelength of a. 50 m. c. 20 m. b. 0.5 m. d. 0.2 m.
    15·1 answer
  • Object A has mass mA = 9 kg and initial momentum vector pA,i = < 20, -6, 0 > kg · m/s, just before it strikes object B, wh
    13·1 answer
  • These problems involve Impulse-Mometum theorem, and the Work-Kinetic Energy theorem. Both theorems are combinations of Newton's
    7·1 answer
  • A boy of 50 kg jumps off a boat (30 kg), causing the boat to move to the right at 2.0 m/s. In what direction and at what velocit
    8·2 answers
  • In diving to a depth of 308 m, an elephant seal also moves 579 m due east of his starting point. What is the magnitude of the se
    8·1 answer
  • Name
    12·2 answers
  • As the velocity of the sound source approaches the speed of sound, the wave fronts ahead of the object begin to appear as:
    5·1 answer
  • Work done by a constant force equal the magnitude of that is force multiplied by what?​
    9·1 answer
  • Tarzans mass is 75kg. calculate his weight
    14·1 answer
  • A constant force of 12 N in the positive x direction acts on a 4.0-kg object as it moves from the origin to the point 6i-8j m. H
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!