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Korvikt [17]
2 years ago
5

Sound wave of a wave length of 0.56 meters if its speed is 280 m/s what is the wave frequency

Physics
1 answer:
Reika [66]2 years ago
5 0

Answer:

500 Hz

Explanation:

Formula for finding wave frequency is,

f = c/λ

f = frequency

c = speed (m/s)

λ = wave length (m)

f = c/λ

f = 280/0.56

f = 500

∴ wave frequency is 500 Hz

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The diagram below shows a person using a device called a jetpack. Water is forced downwards from the jetpack and produces an upw
klasskru [66]

Answer:

The condition necessary for the person to be able to remain stationary in mid-air is that there must be an upward force also referred to as THRUST

Explanation:

Thrust in Physics is defined as the force that propels, forces or pushes the mass of a certain object in a specified or particular direction.

Thrust can defined in the terms of a Jet pack can be defined as the force that is required to propel the mass of a person in an upward direction.

Based on the diagram that we have been shown the question, we can see that water is the fuel used to proper the user or person upwards hence, the jet pack used in the question is an HydroJet pack

The condition necessary for the person to be able to remain stationary in mid-air is that the propelling force called the thrust must be upwards such that it can overcome these 4 things:

a) Gravitational force

b) Mass of the jet pack user

c) Mass of the jet pack itself

d) The water which serves as fuel for the jet pack.

5 0
3 years ago
An object acted on by three forces moves with constant velocity. One force acting on the object is in the positive xx direction
Rudik [331]

Answer with Explanation:

We are given that

F_1=6.9 N

F_2=4.5 N

We have to find the direction and magnitude of the third force acting on the object.

Resultant force,F=\sqrt{F^2_1+F^2_2}

F=\sqrt{(6.9)^2+(4.5)^2}=8.24 N

The object moves with constant velocity .Therefore, net force on object is equal to zero

So,Third force,F_3=F=8.24 N

Direction,\theta=tan^{-1}(\frac{F_2}{F_1})

\theta=tan^{-1}(\frac{4.5}{6.9})=33.02^{\circ}

Angle lies in second quadrant because the direction of third force is opposite to the direction of the resultant force of F1 and F2.

Therefore,\theta=\pi-\theta=180-33.02=146.98^{\circ}

8 0
3 years ago
The linear expansion of a material depends on which of the following?
nordsb [41]

Answer:

1. The change in temperature of the material.

2. The length of the material.

3. The type of material.

Explanation:

The term linear expansion is defined as the increase in length of any conductor when there is a change in temperature. The new length of any wire or rod is given by :

L=L_o(1+\alpha \Delta T)

L_o is the initial length of the rod

\alpha is the coefficient of linear expansion

\Delta T is the change in temperature

It is clear that the linear expansion of a material depends on :

1. The change in temperature of the material.

2. The length of the material.

3. The type of material.

So, all options are correct.

7 0
2 years ago
1. When two atoms of the same nonmetal react, they often form a(an)
kkurt [141]

When two atoms of the same nonmetal react,they form what we know today as a diatomic molecule.

Please mark brainliest. :)

7 0
2 years ago
if you are in Birmingham AL, and you want to use your cell phone to talk to your cousin in Houston, TX, what must occur in order
lesantik [10]

Answer:

For communication to be communicated between you and your cousin who is in Houston,Texas, when a call is made by you, a request is made to the specific phone, and the telephone tower will get the request from the mobile phone. Then a signal is sent via a transmitter underground, by this the satellite communicates with the local receiver in Houston, that is linked to the local tower over there, the tower would request for your cousin's number and connects the two of you, once a link is set.

Explanation:

From the example stated, what is required for such for a far distance, is a communication satellite link.

When a call is made by you, the a connection request is sent to the specified phone.The telephone tower receives the request from The mobile phone. The local tower(Birmingham,Al) is linked to a ground transmitter by the means of a Fiber optical cable.

A signal is sent to satellite via the ground transmitter.The satellite then set's off the local receiver in (Houston,Texas) which on it's end is connected to the local tower there. This tower then ask for your cousin's mobile for a call that will be incoming, a link is set, once he/she receives the call, from there a conversation can be done.

3 0
3 years ago
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