Answer:
<em>D. The total force on the particle with charge q is perpendicular to the bottom of the triangle.</em>
Explanation:
The image is shown below.
The force on the particle with charge q due to each charge Q = 
we designate this force as N
Since the charges form an equilateral triangle, then, the forces due to each particle with charge Q on the particle with charge q act at an angle of 60° below the horizontal x-axis.
Resolving the forces on the particle, we have
for the x-component
= N cosine 60° + (-N cosine 60°) = 0
for the y-component
= -f sine 60° + (-f sine 60) = -2N sine 60° = -2N(0.866) = -1.732N
The above indicates that there is no resultant force in the x-axis, since it is equal to zero ( = 0).
The total force is seen to act only in the y-axis, since it only has a y-component equivalent to 1.732 times the force due to each of the Q particles on q.
<em>The total force on the particle with charge q is therefore perpendicular to the bottom of the triangle.</em>
Answer:
At the high temperatures of the inner solar nebula, the small proto-planets were too hot to hold the volatile gases that dominated the solar nebula. These proto-planets were Earth, Mars, Venus, and Mercury.
Explanation:
The materials that accreted into the early Earth were probably added piecemeal, without and particular order. The early earth was very hot from gravitational compression, impacts and radioactive decay; the earth was partially molted. The denser metallic liquids sank to the center of the Earth and less denser silicate liquids rose to the top. In this way the Earth differentiated very quickly into a metallic, mostly iron core and a rocky silicate mantle.
Answer:
The power for circular shaft is 7.315 hp and tubular shaft is 6.667 hp
Explanation:
<u>Polar moment of Inertia</u>
= 0.14374 in 4
<u>Maximum sustainable torque on the solid circular shaft</u>
=
= 3658.836 lb.in
= 
lb.ft
= 304.9 lb.ft
<u>Maximum sustainable torque on the tubular shaft</u>
= 
= 3334.8 lb.in
= 
lb.ft
= 277.9 lb.ft
<u>Maximum sustainable power in the solid circular shaft</u>
= 
= 4023.061 lb. ft/s
= 
hp
= 7.315 hp
<u>Maximum sustainable power in the tubular shaft</u>
= 
= 3666.804 lb.ft /s
= 
hp
= 6.667 hp
Answer:
= 925.92 N
≅ 926N
Explanation:
Pressure due to car = pressure due to applied force
12000/18^2 = Force / 5^2
force = 12000 * 25/ 324
= 925.92 N
For equilibrium
Pressure1 = Pressure2
A1F1 = A2F2
12000*pi*(5^2) = F2 ( pi)*(18^2)
so, F2 = Applied force to lift car = 925.92 N
Pascal's principle
Pressure1 = Pressure2
F1/A1 = F2/A2 (F=force and A=area)
A1 =Pi*(0.05)²
A2 =Pi(0.18)²
F2=12000
F1 = 12000*(0.05)² / (0.18)² = 926N
Here is the correct answer of the given question above. When a person steps forward out of a small boat onto a dock, the boat recoils backward in the water and this occurs because the total momentum of the system is conserved. Hope this helps.
