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zepelin [54]
3 years ago
15

An investigation was done with an electromagnetic system made from a battery and wire wrapped around a nail. Different sizes of

nails were used. The number of paper clips the electromagnet could pick up was measured. What is the dependent variable in this experiment?
A) the size of nail used
B) the amount of paperclips picked up
C) the size of battery used
D) the type of wire used
Physics
1 answer:
alex41 [277]3 years ago
5 0
Dependant variable is something which you MEASURE during an experiment

So your answer would be : B
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A ball is connected to a light spring suspended vertically. When pulled downward from its equilibrium position and released, the
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Answer:

The forms of energy involved are

1. Kinetic energy

2. Potential energy

Explanation:

The system consists of a ball initially at rest. The ball is pulled down from its equilibrium position (this builds up its potential energy) and then released. The released ball oscillates due to a continuous transition between kinetic and potential energy.

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4 years ago
The difference in potential between the accelerating plates of a TV set is about 24 kV. The distance between these plates is 1.5
ryzh [129]

Answer:

So electric field between the plates will be equal to 1600\times 10^3KN/C

Explanation:

We have given potential difference between accelerating plates = 24 KV = 24000 volt

Distance between the plates d = 1.5 cm = 0.015 m

We know that potential difference is given by V = Ed, here E is electric field and d is distance between plates

So 24000=E\times 0.015

E = 1600000 N/C = 1600\times 10^3KN/C

So electric field between plates will be equal to 1600\times 10^3KN/C

7 0
3 years ago
A block lying on an inclined plane has a weight of 50 N. It just begins to slide down when the inclination of plane with the hor
hjlf

Answer:

μ = tanθ = tan30 = 0.58

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μ = force parallel/force perpendicular = mgsinθ/mgcosθ = tanθ

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A rock thrown with a horizontal velocity of 20m/s from a cliff that is 125m above level ground. If air resistance is negligible,
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3 years ago
A small object with mass 1.30 kg is mounted on one end of arod
Julli [10]

Answer:

(a) I_{system} = 1.014\ kg.m^{2}

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Solution:

As per the question:

Mass of the object, m = 1.30 kg

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Now,

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I_{system} = ML^{2} = 1.30\times (0.780)^{2} = 0.791\ kg.m^{2}

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\tau = FLsin\theta 90 = 2.30\times 10^{- 2}\times 0.780\times 1 = 0.0179\ N-m

3 0
3 years ago
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