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3 years ago

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A force acts on a particle as the particle moves along an x axis, with in newtons, x in meters, and c a constant. At x = 0 m, th

e particle's kinetic energy is 19.0 J; at x = 4.00 m, it is 11.0 J. Find c.

1 answer:

lidiya [134]3 years ago

5 0

Answer:

Incomplete question... We are suppose to be given the force equation and i think it is Fvec = (cx - 3.00x^2)i

Explanation:

Check attachment for solution

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What would the weight of an astronaut be on Saturn if his mass is 68 kg and acceleration of gravity on Saturn is 10.44 m/s2? Ple

alex41 [277]

Here's the part you need to know:

   (Weight of anything) =

   (the thing's mass)
times
       (acceleration of gravity in the place where the thing is) .

   Weight = (mass ) x (gravity) .

That's always true everywhere.
You should memorize it.

For the astronaut on Saturn . . .

   Weight = (mass ) x (gravity) .

   Weight = (68 kg) x (10.44 m/s²)

   = 709.92 newtons .
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On Earth, gravity is only 9.8 m/s².
So as long as the astronaut is on Earth, his weight is only

   (68 kg) x (9.8 m/s²)

   = 666.4 newtons .

Notice that his mass is his mass ... it doesn't change
no matter where he goes.

But his weight changes in different places, because
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3 years ago

When you lift a bowling ball with a force of 61.1 N, the ball accelerates upward with an acceleration a. If you lift with a forc

gtnhenbr [62]

Answer:

the weight of the ball is w = 51.94 N ( mass = 5.3 kg)

Explanation:

Following Newton's second law:

net force = mass * acceleration = weight/gravity * acceleration

then denoting 1 and 2 as the first and second lift

F₁ - w= w/g *a₁

F₂ -w = w/g *a₂ = w/g * 2.07a

dividing both equations

(F₂- w)/(F₁ -w)= 2.07

(F₂- w) = 2.07 * (F₁ -w)

1.07*w = 2.07*F₁ - F₂

w = (2.07*F₁ - F₂ )/ 1.07

replacing values

w = (2.07*61.1 N - 70.9 N )/ 1.07 = 51.94 N

then the weight of the ball is w = 51.94 N ( mass = 5.3 kg)

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3 years ago

The coefficient of linear expansion of copper is 17 x 10^-6 K-1. A block of copper 30 cm wide, 45 cm long, and 10 cm thick is he

schepotkina [342]

Answer:

The change in volume is $6.885\times 10^{- 5}\$

Solution:

As per the question:

Coefficient of linear expansion of Copper, $\alpha = 17\times 10^{- 6}\ K^{- 1}$

Initial Temperature, T = $0^{\circ}$ = 273 K

Final Temperature, T' = $100^{\circ}$ = 273 + 100 = 373 K

Now,

Initial Volume of the block, V = $30\times 45\times 10\times 10^{- 6}\ m^{3} = 0.0135\ m^{3}$

$V' = V(1 + \gamma \Delta T)$

$\gamma = 3\alpha$

$V' = V(1 + 3\alpha \Delta T)$

where

V' = Final volume

$V' - V= 0.0135\times 17\times 10^{- 6} \times (T' - T))$

$\Delta V= 0.0135\times 3\times 17\times 10^{- 6} \times (373 - 273)) = 6.885\times 10^{- 5}\$

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3 years ago

Are the two atoms shown below in the image from the same element?

kvasek [131]

The answer is yes

They are isotopes.

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3 years ago

Explain how the plants of a tropical rain forest contribute to the characteristic hot, humid weather associated with the area. U

Talja [164]

Answer: The atmosphere of trophic rainforest is hot and humid due to high rate of transpiration.

Explanation:

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3 years ago