Answer: Magnitude of electrical force stays the same.
Explanation:
Equation:

Since the magnitude of each charge is halved.
and
the separation is halved.


Cancel out .25 on the numerator and denominator. Leaving the original equation.
Answer:
2123.55 $/hr
Explanation:
Given parameters are:
KV
L = 143 km
I = 500 A

So, we will find the voltage potential provided for the city as:
kV
kV
Then, we will find dissipated power because of the resistive loss on the transmission line as:
W
Since the charge of plant is not given for electric energy, let's assume it randomly as 
Then, we will find the price of energy transmitted to the city as:
$/hr
To calculate money per hour saved by increasing the electric potential of the power plant:
Finally,
$/hr
The amount of money saved per hour =
$/hr
Note: For different value of the price of energy, it just can be substituted in the equations above, and proper result can be found accordingly.
Answer:
Prevost's theory of exchanges stated that each body radiates to, and receives radiation from, other bodies. ... Prevost went on to comment that "The heat of several portions of space at the same temperature, and next to one another, is at the same time in the two species of equilibrium."
Explanation:
Answer:
Acceleration:
C. Meters per second squared
Velocity:
B. Meters per second
Distance:
A. Meters
Explanation:
We must remember that the international system of measures (SI) takes into account for the length as the main unit the meter, for the mass the kilogram, for the time the second.
The acceleration is calculated using the following expression
a = v/t = (m/s/s) = (m/s^2]
The velocity is calculated using the following expression
v = x/t = (m)/(s) = (m/s)
The distance for the SI system is given in meters
Answer:
E=0
Explanation:
Electric field due to each thin sheet of charge=\sigma/2\varepsilon
let us say the right plate has positive charge density \varepsilonand left sheet has a negative charge density -\varepsilon .
In the region between the plates,the electric field due to each plate is in same direction,
E=\sigma/2\varepsilon-(-\sigma/2\varepsilon)
E=\sigma/\varepsilon
in the region outside the plates, the field due to the plates is in opposite directions
E=-\sigma/2\varepsilon-(-\sigma/2\varepsilon)
E=-\sigma/2\varepsilon+\sigma/2\varepsilon
E=0