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____ [38]
3 years ago
13

Which of these forms of radiation passes most easily through the disk of the Milky Way?

Physics
1 answer:
Rama09 [41]3 years ago
4 0
<h2>Answer: 3 - infrared light</h2>

Explanation:

<u>There are certain areas of the Milky Way that cannot be observed using the visible range of the electromagnetic spectrum</u> (this includes blue light and red light). This is because these areas are covered or hidden behind columns of interstellar dust and dark matter.

However, using infrared light and sometimes radio waves, it is possible to observe the galaxy better, because this light manages to pass through all that interstellar dust.

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pochemuha
<span>When temperature is increased, the rate of dissolving increases. The kinetic energy of the molecules of the solute and solvent molecules is high thereby increasing their contact. An example is mixing powdered sugar to the water. When you add water to the sugar, the dissolving process is slow. However, when you increase the temperature of the water by boiling it, the sugar dissolves immediately. </span>
3 0
3 years ago
A snail crawls 300 cm in 1 hour. Calculate the snail's speed in each of the following units. a. centimeters per hour (cm/h) b. c
guajiro [1.7K]
It would be 300 cm/h
and 5 cm/m
4 0
3 years ago
The force of gravity acting on an object is the object's ______. A. acceleration B. mass C. weight D. matter
ryzh [129]

Answer:

d

Explanation:

3 0
2 years ago
Read 2 more answers
A square plate of edge length 9.0 cm and negligible thickness has a total charge of 6.90 10-6 C. Estimate the magnitude E of the
SVETLANKA909090 [29]

Answer:

E= 4.35*10^6 N/C

Explanation:

Let's find the area charge density of the plate

α= 6.9*10^-6/9*10^-2 = 7.7*10^-5C/m2

Now we can calculate the electric field just of the plate

E =α/2e =7.7*10^-5/2*8.85*10^-12 = 4.35*10^6 N/C

7 0
3 years ago
What is the distance of separation between objects of masses 5.6 x 10 5 kg and 8.8 x 10 6 kg if the force of gravity between the
AlladinOne [14]

Answer:

2.87m

Explanation:

Using the law of gravitation to solve this question

F = GMm/r²

G is the gravitational constant

M and m are the masses

r is the distance between the masses

Substitute the given values

G = 6.67×10^-11 m³/kgs²

M =8.8 x 10^6 kg

m = 5.6 x 10^5 kg

F =440N

400 = 6.67×10^-11×8.8 x 10^6 ×5.6 x 10^5/r²

400r² = 328.698×10

400r² = 3286.98

r² = 3286.98/400

r² = 8.21745

r = √8.21745

r = 2.87m

Hence the distance of separation is 2.87m

7 0
3 years ago
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