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3 years ago

Which of these forms of radiation passes most easily through the disk of the Milky Way?

Physics

1 answer:

Rama09 [41]3 years ago

4 0

<h2>Answer: 3 - infrared light</h2>

Explanation:

<u>There are certain areas of the Milky Way that cannot be observed using the visible range of the electromagnetic spectrum</u> (this includes blue light and red light). This is because these areas are covered or hidden behind columns of interstellar dust and dark matter.

However, using infrared light and sometimes radio waves, it is possible to observe the galaxy better, because this light manages to pass through all that interstellar dust.

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Can anyone help with these questions please

Svet_ta [14]

Here... I've finished this course already

6 0

3 years ago

If you hold a permanent magnet the wrong way in an extremely strong magnetic f eld, its magnetization will be permanently revers

Phoenix [80]

Answer: The domain that is aligned with the applied field will grow, while the domain that is oppositely aligned to the magnetic field will shrink, this is because permanent magnets produces their own magnetic field.

4 0

3 years ago

A metal wire 1.50 m long has a circular cross section of radius 0.32 mm and an end-to-end resistance of 90.0 Ohms. The metal wir

elixir [45]

Answer:

So after stretching new resistance will be 0.1823 ohm

Explanation:

We have given initially length of the wire $l_1=150m$

Radius of the wire $r_1=0.32mm=0.32\times 10^{-3}m$

Resistance of the wire initially $R_1=90ohm$

We know that resistance is equal to $R=\frac{\rho l}{A}$ ,here $\rho$ is resistivity, l is length and A is area

From the relation we can say that $\frac{R_1}{R_2}=\frac{l_1}{l_2}\times \frac{A_2}{A_1}$

Now length of wire become 6.75 m

Volume will be constant

So $A_1l_1=A_2l_2$

So $\pi \times (0.32)^2\times150=\pi \times r_2^2\times 6.75$

$r_2=1.508mm$

So $\frac{90}{R_2}=\frac{150}{6.75}\times \frac{1.508^2}{0.32^2}$

$R_2=0.1823ohm$

7 0

3 years ago

A 3.00 kg stone is dropped from a 39.2 m high building. when the stone has fallen 19.6 m, the magnitude of the impulse the earth

tatiyna

<span>The formulas are, Impulse = mv-mu ....... (1) v^2 = u^2 + 2as .......... (2) We know that, u=0 a=acceleration=gravity = 9.80665 m/s^2 = 9.81 m/s^2 s=19.6 sub (2) we get, v^2 = 0+ 2*9.81*19.6 v^2 = 2*9.81*19.6 v^2 = 384.552 v = 19.6099 v = 19.61 m/s Sub v=19.61 m/s in (1) we get, Impulse = mv - mu we know that u=0; v= 19.61 m/s; m= 3.00 kg Impulse = 3(19.61) - 3(0) Impulse = 58.83-0 Impulse = 58.83 Ns. Therefore the gravitational force exerted by the stone is 58.83 Ns.</span>

4 0

4 years ago

Joan wants to test if salt lowers the temperature at which water boils.

ohaa [14]

In order to build a hypothesis, Joan should take an educated guess at what the effect of adding salt to the water will be on the water's boiling point. For example, the hypothesis may be,"The boiling point will increase". This hypothesis is one that can be verified or rejected via experimentation. The next step for Joan would be to set up an experiment to test this hypothesis.

6 0

3 years ago

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