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LUCKY_DIMON [66]
3 years ago
10

Steve can run 3.5 miles in 30 minutes. If Steve increases his rate by 1/2 mile per hour, how far will he run in 2 hours?

Mathematics
2 answers:
Sati [7]3 years ago
7 0

Answer:

15 miles

Step-by-step explanation:

Steve runs 3.5 miles in 30 minutes (0.5 hours).  So his speed is:

r = 3.5 mi / 0.5 h

r = 7 mi/h

If his rate increases to 7.5 mi/h, the distance he runs in 2 hours is:

d = 7.5 mi/h × 2 h

d = 15 mi

faust18 [17]3 years ago
6 0

Answer:

15 mis

Step-by-step explanation:

cuz he run 3.5 miles in 30 minutes (0.5 hours).  So his speed is:

d = 7.5 mi/h × 2 h

d = 15 mi

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10 The collection of distinct vowel letters from the words PNEUMONOULTRAMICROSCOPICSILICOVOLCANOCONIOSIS​
irina1246 [14]

The collection of distinct vowel letters from the words PNEUMONOULTRAMICROSCOPICSILICOVOLCANOCONIOSIS​

The words' vowel letters are [A,,E,I,O,U].

A, E, I, O, U, Y, and, as we'll see, W are vowels, but let's go more precise now. They are symbols (letters) that represent a certain kind of spoken sound called a vowel. According to phoneticians, a vowel is a spoken sound that is made without severely limiting the airflow from the lungs.

The alphabet consists of 26 letters, five of which are vowels (a, e, I, o, and u). The other letters are consonants. A vowel is a sound made by opening the mouth and allowing air to escape without closing it or clearing the throat.

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4 0
2 years ago
Can anyone help me?​
svp [43]

Answer:

Literally take your f(x) and - your g(x)

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Remember to distribute the negative sign.

6 0
3 years ago
Newborn babies: A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights
Fed [463]

Answer:

a) 615

b) 715

c) 344

Step-by-step explanation:

According to the Question,

  • Given that,  A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 732 babies born in New York. The mean weight was 3311 grams with a standard deviation of 860 grams

  • Since the distribution is approximately bell-shaped, we can use the normal distribution and calculate the Z scores for each scenario.

Z = (x - mean)/standard deviation

Now,

For x = 4171,  Z = (4171 - 3311)/860 = 1  

  • P(Z < 1) using Z table for areas for the standard normal distribution, you will get 0.8413.

Next, multiply that by the sample size of 732.

  • Therefore 732(0.8413) = 615.8316, so approximately 615 will weigh less than 4171  

 

  • For part b, use the same method except x is now 1591.    

Z = (1581 - 3311)/860 = -2    

  • P(Z > -2) , using the Z table is 1 - 0.0228 = 0.9772 . Now 732(0.9772) = 715.3104, so approximately 715 will weigh more than 1591.

 

  • For part c, we now need to get two Z scores, one for 3311 and another for 5031.

Z1 = (3311 - 3311)/860 = 0

Z2 = (5031 - 3311)/860= 2  

P(0 ≤ Z ≤ 2) = 0.9772 - 0.5000 = 0.4772

  approximately 47% fall between 0 and 1 standard deviation, so take 0.47 times 732 ⇒ 732×0.47 = 344.

5 0
3 years ago
Find the radius of a circle using the Pythagorean theorem, given that the center is at (1, 5) and the point (5, 1) lies on the c
Assoli18 [71]

Given :

Center of circle, C = ( 1 , 5 )

Point on circle, P = ( 5 , 1 )

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Solution :

We know, radius of circle is the distance between center and point of circle.

Distance between two points A(p,q) and B(r,s) is given by :

D = \sqrt{(p-r)^2+(q-s)^2}

So, distance between the points (1, 5) and (5, 1) is :

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Therefore, radius of circle is 5.66 units.

Hence, this is the required solution.

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ASHA 777 [7]

Answer:

When we have a rotation about a given point, the distance between the rotated point and the axis of rotation will remain constant, the only thing that changes is the coordinates of the point.

This tell us that the main measures of any rotated shape will not change.

Then the side lengths will remain constant, this implies that the area also remains constant, and this also means that the angle measures should remain the same.

And because the perimeter is equal to the sum of all the side lengths, the perimeter also remains the same.

The only thing that changes will be the coordinates of our polygon.

4 0
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