Answer:
It is A.Heat is transmitted and light is reflected.
niAnswer:
(A) Vx = -9.14ωCosωt,
Vy = 9.14ωSinωt
(B) ax =9.14ω²Sinωt,
ay = 9.14ω²Cosωt
Explanation:
The velocity of a body ia the time derivative of the poaition function of the body with respect to time. Given equations x = −9.14 sin ωt and y = 4.00 − 9.14 cos ωt,
All we need to do to get the velocity is to differentiate each of the equation above with respect to time in order to get Vx and Vy required of us.
Vx = dx/dt = -9.14ωCosωt and
Vy = dy/dt = 9.14ωSinωt
In order to get the acceleration we differentiate the velocity function with respect to time. That is,
A = dv/dt
ax = dVx/dt = 9.14ω²Sinωt
ay = dVx/dt = 9.14ω²Cosωt
The nucleus is always positive since thats where the protons are located and the neutrons have no charge....
Answer:
6.20×10⁴ V/m
Explanation:
The magnitude of electric field is:
E = √(Eₓ² + Eᵧ²)
where Eₓ = ∂φ/∂x and Eᵧ = ∂φ/∂y.
φ = 1.11 (x² + y²)^-½ − 429x
Eₓ = -0.555 (x² + y²)^-(³/₂) (2x) − 429
Eᵧ = -0.555 (x² + y²)^-(³/₂) (2y)
Evaluating at (0.003, 0.003):
Eₓ = -44034 V/m
Eᵧ = -43605 V/m
The magnitude is:
E = 61971 V/m
Rounded to three significant figures, the strength of the electric field is 6.20×10⁴ V/m.