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3 years ago

What is one of Kepler's laws of planetary motion?

Physics

1 answer:

iragen [17]3 years ago

4 0

Answer:

a. Planets move on elliptical orbits with the Sun at one focus.

Explanation:

Johannes Kepler was an astronomer who discovered that planets had elliptical orbits in the early 1600s (between 1609 and 1619).

The three (3) laws published by Kepler include;

I. The first law of planetary motion by Kepler states that, all the planets move in elliptical orbits around the Sun at a focus.

II. According to Kepler's second law of planetary motion, the speed of a planet is greatest when it is closest to the Sun.

Thus, the nearer (closer) a planet is to the Sun, the stronger would be the gravitational pull of the sun on the planet and consequently, the faster is the speed of the planet in terms motion.

III. The square of any planetary body's orbital period (P) is directly proportional to the cube of its orbit's semi-major axis.

Hence, one of Kepler's laws of planetary motion states that planets move on elliptical orbits with the Sun at one focus. This is his first law of planetary motion.

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If two temperatures differ by 25 degrees on Celsius scale, the difference of temperature on Fahrenheit scale is?

Mekhanik [1.2K]

Answer:

25 x 9/5 = 45 degrees Fahrenheit

Explanation:

4 0

2 years ago

You stand17.5 m from a wall holding a baseball. You throw the baseball at the wall at an angle of 20.5∘ from the ground with an

Lelechka [254]

Answer: 8.8 m

Explanation:

The movement of the baseball to the wall is a example of parabolic motion. While the baseball aproach the wall it is affected by gravity.

In this case, because the Initial Velocity of the ball is a vecotr, it can be defined using its two directionals compounds. One, on the Y-axis and another on the X-axis. This can be related, on how a hypotenuse is the product of two legs of the triangle. Because of this, each one of this, can be know using the following equation:

Vx = Vo * cos(∅)

Vy = Vo * sin(∅)

Where Vo is the initial velocity 27.5 m/s, and ∅ is the angle which is 20.5°. So we calculate:

Vx = 27.5m/s * cos(20.5)

Vx = 27.5m/s * 0.936

Vx = 25.74m/s

Vy = 27.5m/s * sin(20.5)

Vy = 9.62m/s

Now the movement is divided on two parts, one under the effect of gravity and another one with a constant velocity.

To know how tall does the baseball hit the wall, we need to know first how much time it takes the ball to reach the wall on the X-axis. The wall is 17.5m away, we velocity on Vx that is constant we can calculate as it follow:

Time (T) = Distance (D) / Velocity (V)

Where Distance is 17.5m and our Velocity is the Vx calculated before.

T = 17.5 m / 25.74m/s

T = 0.68s

This is the time it takes the ball to reach the wall.

Know with the time, we can calculate the how tall it got on that time with the following equation:

$x = (Vo*t) + (\frac{1}{2} *a*t^{2} )$

Where Vo is the Y-Compound of the Initial Velocity.

a is the aceleration, in this case the Gravity. Which, will be negative because is oposing the movement. Gravity is equal to 9.81 $m/s^{2}$

And t is the time it takes the ball to get to the wall.

$x = (Vy*T) + (\frac{1}{2} *g*T^{2} )$

$x = ((9.62m/s)*0.68s) + (\frac{1}{2} *(9.81m/s^{2})*(0.68s)^{2} )$

$x = 8.8 m$

This is the height that the baseball touch the wall.

6 0

3 years ago

Based on your calculations in Activity 3.7B, what are the rates of seafloor spreading for the North Atlantic basin ______cm/yr

Over [174]

It was be at least 67 cm/yr for the North Atlantic

3 0

4 years ago

A proton is shot perpendicularly at an infinite plane of charge. The charge density of the plane is +7.65×10^−4 C/m^2. If the pr

Alexeev081 [22]

Answer:

The velocity is $2.94\times10^{6}\ m/s$ .

Explanation:

Given that,

Charge density of the plane $\sigma=7.65\times10^{−4}\ C/m^2$

Distance = 1.05 mm

We need to calculate the electric field due to plane of charge

Using formula of electric field

$E=\dfrac{\sigma}{2\epsilon}$

Put the value into the formula

$E=\dfrac{7.65\times10^{−4}}{2\times8.85\times10^{-12}}$

$E=4.322\times10^{7}\ N/C$

We need to calculate potential difference

Using formula of potential difference

$V=E\times r$

Put the value into the formula

$V=4.322\times10^{7}\times1.05\times10^{-3}$

$V=4.5381\times10^{4}\ Volt$

We need to calculate the work requires to be done to reach the surface of the plane

Using formula of work done

$W=qV$

Put the value into the formula

$W = 1.6\times10^{-19}\times4.5381\times10^{4}$

$W=7.26096\times10^{-15}\ J$

We need to calculate the velocity

Using work energy theorem

$W=\dfrac{1}{2}mv^2$

$v^2=\dfrac{2W}{m}$

$v=\sqrt{\dfrac{2\times7.26096\times10^{-15}}{1.67\times10^{-27}}}$

$v=2.94\times10^{6}\ m/s$

Hence, The velocity is $2.94\times10^{6}\ m/s$ .

8 0

3 years ago

What is the importance of time ?

lesantik [10]

I think that the importance of time is to allow there to be order. People need to be somewhere at a certain time and not just whenever they want. It allows people to get things done more efficiently. <span />

8 0

3 years ago