Should be 4x5x4!! If you take 8•15, you get 120!! There are six sides on a rectangular prism!! Thus leaving a value of 20 per side!! And I noted to properly equal out with the maximum volume it should mean 4•5=20!! Thus being 4•4•5
Answer:
![0.293I_0](https://tex.z-dn.net/?f=0.293I_0)
Explanation:
When the unpolarized light passes through the first polarizer, only the component of the light parallel to the axis of the polarizer passes through.
Therefore, after the first polarizer, the intensity of light passing through it is halved, so the intensity after the first polarizer is:
![I_1=\frac{I_0}{2}](https://tex.z-dn.net/?f=I_1%3D%5Cfrac%7BI_0%7D%7B2%7D)
Then, the light passes through the second polarizer. In this case, the intensity of the light passing through the 2nd polarizer is given by Malus' law:
![I_2=I_1 cos^2 \theta](https://tex.z-dn.net/?f=I_2%3DI_1%20cos%5E2%20%5Ctheta)
where
is the angle between the axes of the two polarizer
Here we have
![\theta=40^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D40%5E%7B%5Ccirc%7D)
So the intensity after the 2nd polarizer is
![I_2=I_1 (cos 40^{\circ})^2=0.587I_1](https://tex.z-dn.net/?f=I_2%3DI_1%20%28cos%2040%5E%7B%5Ccirc%7D%29%5E2%3D0.587I_1)
And substituting the expression for I1, we find:
![I_2=0.587 (\frac{I_0}{2})=0.293I_0](https://tex.z-dn.net/?f=I_2%3D0.587%20%28%5Cfrac%7BI_0%7D%7B2%7D%29%3D0.293I_0)
Explanation:
(a) Displacement of an object is the shortest path covered by it.
In this problem, a student is biking to school. She travels 0.7 km north, then realizes something has fallen out of her bag. She travels 0.3 km south to retrieve her item. She then travels 0.4 mi north to arrive at school.
0.4 miles = 0.64 km
displacement = 0.7-0.3+0.64 = 1.04 km
(b) Average velocity = total displacement/total time
t = 15 min = 0.25 hour
![v=\dfrac{1.04\ km}{0.25\ h}\\\\v=4.16\ km/h](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7B1.04%5C%20km%7D%7B0.25%5C%20h%7D%5C%5C%5C%5Cv%3D4.16%5C%20km%2Fh)
Hence, this is the required solution.