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GalinKa [24]
3 years ago
13

On a violin, the highest note Mandy can play is an A-note, which produces a sound wave with a high frequency. The lowest note sh

e can play is a G-note, which has a low frequency.
How does the wavelength of a G-note sound wave compare to the wavelength of an A-note sound wave?
The G-note's wavelength is the same size.
The G-note's wavelength is shorter.
The G-note's wavelength is longer.
There is not enough information to tell.
Physics
2 answers:
lora16 [44]3 years ago
6 0
I think the answer would be: The G-note's wavelength is longer

Here are the formula to calculate wavelength

Wavelength = Wave speed/Frequency

Which indicates that the wavelength will become larger as the frequency became smaller.

polet [3.4K]3 years ago
4 0

Its the G-note wavelength is longer

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D section a only still need help on this
SIZIF [17.4K]

Acceleration means speeding up, slowing down, or changing direction. The graph doesn't show anything about direction, so we just have to examine it for speeding up or slowing down ... any change of speed.

The y-axis of this graph IS speed. So the height of a point on the line is speed. If the line is going up or down, then speed is changing.

Sections a, c, and d are all going up or down. Section b is the only one where speed is not changing. So we can't be sure about b, because we don't know if the track may be curving ... the graph can't tell us that. But a, c, and d are DEFINITELY showing acceleration.

5 0
3 years ago
If 3600 j of work is done in 3.0 s what is the power<br>0.00083W<br>1200W<br>3600W<br>11000W
Viktor [21]

Answer:

1200 W

Explanation:

Power is given by the ratio between work done and time taken:

P=\frac{W}{t}

where W is the work done and t the time taken.

In this problem, W = 3600 J and t = 3.0 s. Therefore, the power in this exercise is

P=\frac{3600 J}{3.0 s}=1200 W

5 0
3 years ago
Read 2 more answers
How large is the acceleration of a 25 kg mass with a net force of 75 N applied horizontally to it?
Sveta_85 [38]

Answer:

Explanation:

F = ma

a = F/m

a = 75/25

a = 3 m/s²

8 0
2 years ago
A golf club with mass 0.5 kg is swung at 23 m/s toward a stationary golf ball on a tee. The club barely slows down to 17 m/s, bu
mylen [45]

Answer:

I gotchu fam. 0.0435 kg

Explanation:

m1v1+m2v2=m1v1f+m2v2f

(0.5)(23)+(m2)(0)=(0.5)(17)+(m2)(69)

11.5=8.5+69m2

3=69m2

0.0435 kg

5 0
2 years ago
A 1.1-kg uniform bar of metal is 0.40 m long and has a diameter of 2.0 cm. When someone bangs one end of this bar, a 1.5 MHz sho
lyudmila [28]

Answer:

\lambda = 2.22\times 10^{-3}\ m

Explanation:

Given,

mass of the bar = 1.1 Kg

length of rod, l = 0.40 m

diameter of the rod, d = 2 cm

frequency, f = 1.5 MHz

time, t = 0.12 ms

wavelength of the shock wave = ?

Speed of the wave =\dfrac{L}{t}=\dfrac{0.40}{0.12\times 10^{-3}}

   v = 3333.33 m/s

wavelength of the wave

\lambda = \dfrac{v}{f}= \dfrac{3333.33}{1.5\times 10^6}

\lambda = 2.22\times 10^{-3}\ m

6 0
2 years ago
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