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Marizza181 [45]
3 years ago
11

Two toddlers are fighting over a toy. Joey pulls the toy with a force of 8 N while Tommy pulls the toy with a force of 7.5 N. Wh

at is the net force of the toy? Who is going to get the toy?
Physics
1 answer:
Firdavs [7]3 years ago
5 0

Answer:

15.5 and Joey will get the toy

Explanation:

Net force is all the forces acting on the object and since Joey is pulling .5 newtons more he will get the toy.

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A cruise ship is moving at constant speed through the water. The vacationers on the ship are eager to arrive at their next desti
MArishka [77]

Answer: 1. higher than it was before they started running

Explanation: As the vacationers run towards the back(stern) of the ship the exerting more pressure against the pressure exerted by the wave supporting the moving ship,the pressure exerted on the moving ship will be increased, leading to a slight increase in the speed of the ship compared to the speed before they started running towards the back(stern) of the ship.

6 0
3 years ago
Can someone answer pls??​
SCORPION-xisa [38]

Answer:

2. the volume of the square are the same

7 0
2 years ago
Read 2 more answers
Compared to its weight on Earth, a 5kg object on the moon will weigh
shutvik [7]

Answer:

8.1 N/49 N=0.1653  which means 16.53% of the weight of the object on Earth.

Explanation:

On the Moon, where the gravitational constant is 1.62 \frac{m}{s^2}, the weight of the 5 kg object will be: weight_M=m*g_M = 5 kg * 1.62 \frac{m}{s^2} =8.1 N

Where the answer is in Newtons (N) since all quantities are given in the SI system.

On Earth, on the other hand, the weight of the object is:

weight_E=m*g_E= 5 kg* 9.8 \frac{m}{s^2} = 49N

Therefore the object's weight on the Moon compared to that on Earth will be:

8.1N/49N=0.1653

That is, 16.53% of the weight the object has on Earth.

5 0
4 years ago
Answer it asap<br> I promise i will mark them the Brainly
nataly862011 [7]

Answer:

A) The acceleration is zero

<em>B) The total distance is 112 m</em>

Explanation:

<u>Velocity vs Time Graph</u>

It shows the behavior of the velocity as time increases. If the velocity increases, then the acceleration is positive, if the velocity decreases, the acceleration is negative, and if the velocity is constant, then the acceleration is zero.

The graph shows a horizontal line between points A and B. It means the velocity didn't change in that interval. Thus the acceleration in that zone is zero.

A. To calculate the acceleration, we use the formula:

\displaystyle a=\frac{v_2-v_1}{t_2-t_1}

Let's pick the extremes of the region AB: (0,8) and (12,8). The acceleration is:

\displaystyle a=\frac{8-8}{12-0}=0

This confirms the previous conclusion.

B. The distance covered by the body can be calculated as the area behind the graph. Since the velocity behaves differently after t=12 s, we'll split the total area into a rectangle and a triangle.

Area of rectangle= base*height=12 s * 8 m/s = 96 m

Area of triangle= base*height/2 = 4 s * 8 m/s /2= 16 m

The total distance is: 96 m + 16 m = 112 m

4 0
3 years ago
If a car changes ita velocity from 32km/hr to 54km/hr in 8.0 seconds, what is its acceleration
Andrews [41]
Firstly, let's convert the velocities in km/hr to m/s
32*1000/3600=8.89m/s
54*1000/3600=15m/s
From the formula, acceleration=V-U/t
15-8.89/8=0.76m/s²
hope this helps.
7 0
3 years ago
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