Answer:
0.992 m
Explanation:
x = (horizontal vi)t + (1/2)at²
18 = (40)t + 0
t = 0.45 s
y = (vertical vi)t + (1/2)gt²
y = 0 + (1/2)(9.8)(0.45)²
y = 0.992 m
The electric potential energy of the electron depends on the potential difference applied between the two ends of the cable. Indeed, the electric potential energy of a charge is given by
![U=q \Delta V](https://tex.z-dn.net/?f=U%3Dq%20%5CDelta%20V)
where q is the magnitude of the charge, while
![\Delta V](https://tex.z-dn.net/?f=%5CDelta%20V)
is the potential difference applied. So, U depends on
![\Delta V](https://tex.z-dn.net/?f=%5CDelta%20V)
.
The intensity of the electric field is 30,000 N/C
Explanation:
The strength of the electric field produced by a single-point charge is given by the equation
where:
is the Coulomb's constant
q is the magnitude of the charge
r is the distance from the charge
In this problem, we have:
is the magnitude of the charge
r = 3 cm = 0.03 m is the distance at which we are calculating the field intensity
Substituting, we find:
![E=(8.99\cdot 10^9)\frac{3\cdot 10^{-9}}{(0.03)^2}=30,000 N/C](https://tex.z-dn.net/?f=E%3D%288.99%5Ccdot%2010%5E9%29%5Cfrac%7B3%5Ccdot%2010%5E%7B-9%7D%7D%7B%280.03%29%5E2%7D%3D30%2C000%20N%2FC)
Learn more about electric field:
brainly.com/question/8960054
brainly.com/question/4273177
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Answer:
make a parachute out of the bag connecting to a bowl made out of paper filled with cotton balls. then put the egg in the bowl.
Explanation:
The hot gases produce their own characteristic pattern of spectral lines, which remain fixed as the temperature increases moderately.
<h3><u>Explanation: </u></h3>
A continuous light spectrum emitted by excited atoms of a hot gas with dark spaces in between due to scattered light of specific wavelengths is termed as an atomic spectrum. A hot gas has excited electrons and produces an emission spectrum; the scattered light forming dark bands are called spectral lines.
Fraunhofer closely observed sunlight by expanding the spectrum and a huge number of dark spectral lines were seen. "Robert Bunsen and Gustav Kirchhoff" discovered that when certain chemicals were burnt using a Bunsen burner, atomic spectra with spectral lines were seen. Atomic spectral pattern is thus a unique characteristic of any gas and can be used to independently identify presence of elements.
The spectrum change does not depend greatly on increasing temperatures and hence no significant change is observed in the emitted spectrum with moderate increase in temperature.