The Force on the left hand pole, F' = 0.167N
<h3>What is the force on the left hand pole?</h3>
Force is an agent which produces a change in the motion or state of an object.
Force is a vector quantity.
The general force is calculated as follows:
F = mg/sinθ
m = 17.1 g = 0.0171 kg
g = 9.81 m/s²
θ = 45°
F = 0.0171 * 9.81/sin45
F = 0.237 N
Force on the left hand pole, F' = Fcosθ
F' = 0.237 * cos 45
F' = 0.167N
In conclusion, the force on the left hand pole is the horizontal component of force.
Learn more about force at: brainly.com/question/141439
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I think it is B. Sorry if I’m wrong
Given:
10^10 electrons per second
To justify that coulomb is a very large unit for practical use, we need to convert the quantity of electron given to Coulombs:
From literature,
1 Coulomb is equivalent to 6.242×10^18 electrons<span>.
So,
= 10^10 electrons * (1 coulomb/</span><span>6.242×10^18</span> electrons) / second
<span>= 1.602 x 10^-9 coulumbs
This value is too small to be used in an actual setting.
</span><span>
</span>
Answer:
Gravity
Explanation:
Due to earths gravity, anything that goes into the air returns back to the surface unless it is given the ability to fly.
Hope this helps!
Solar energy and Geothermal energy are your answers :)
