Question

What is the area of a square with side length of 4 and one-fourth m?

Answer 1

Answer: Third option.

Step-by-step explanation:

The area of a square can be found with this formula:

$A=s^2$

Where "s" is the length of any side of the square.

In this case, you know that:

$s=4\frac{1}{4}\ m$

You can convert from Mixed number to an Improper fraction multipliying the Whole number part by the denominator and add this product to the numerator of the fraction. The denominator does not change. Then:

$s=\frac{(4*4)+1=}{4}\ m\\\\s=\frac{17}{3} \ m$

Substitute the value of "s" into the formula and evaluate:

$A=(\frac{17}{4} \ m)^2\\\\A=\frac{289}{16} \ m^2\\\\A=18.0625\ m^2$

Since:

$0.625=\frac{1}{16}$

You the that the area expressed as a Mixed number is:

$A=18\frac{1}{16}\ m^2$

Answer 2

Answer:

18 and StartFraction 1 Over 16 EndFraction meters squared

Step-by-step explanation:

Area of a square is given by

A=l*l=l² since both sides are equal. Where l is length of one side.

Given that one side measurea 4 and one-fourth m

4¼m

Then substituting this for length, the area will be

4¼*4¼=17/4*17/4=289/16=18 and 1/16 m²

From the given options, the area is

18 and StartFraction 1 Over 16 EndFraction meters squared